See the electrical circuit shown in this figure. Which of the following is a correct equation for it?
1. | \(\varepsilon_1-(i_1+i_2)R-i_1r_1=0\) |
2. | \(\varepsilon_2-i_2r_2-\varepsilon_1-i_1r_1=0\) |
3. | \(-\varepsilon_2-(i_1+i_2)R+i_2r_2=0\) |
4. | \(\varepsilon_1-(i_1+i_2)R+i_1r_1=0\) |
A current of \(3~\text{A}\) flows through the \(2~\Omega\) resistor shown in the circuit. The power dissipated in the \(5~\Omega\) resistor is:
1. | \(4~\text{W}\) | 2. | \(2~\text{W}\) |
3. | \(1~\text{W}\) | 4. | \(5~\text{W}\) |
A cell can be balanced against 100 cm and 110 cm of potentiometer wire, respectively with and without being short-circuited through a resistance of 10 Ω. Its internal resistance is:
1. 1.0 Ω
2. 0.5 Ω
3. 2.0 Ω
4. zero
The total power dissipated in watts in the circuit shown below is:
1. | 16 W | 2. | 40 W |
3. | 54 W | 4. | 4 W |
Three resistances \(\mathrm P\), \(\mathrm Q\), and \(\mathrm R\), each of \(2~\Omega\) and an unknown resistance \(\mathrm{S}\) form the four arms of a Wheatstone bridge circuit. When the resistance of \(6~\Omega\) is connected in parallel to \(\mathrm{S}\), the bridge gets balanced. What is the value of \(\mathrm{S}\)?
1. \(2~\Omega\)
2. \(3~\Omega\)
3. \(6~\Omega\)
4. \(1~\Omega\)
1. | flow from \(A\) to \(B\) |
2. | flow in the direction which will be decided by the value of \(V\) |
3. | be zero |
4. | flow from \(B\) to \(A\) |
The power dissipated across the 8 Ω resistor in the circuit shown here is 2 W. The power dissipated in watts across the 3 Ω resistor is:
1. | 2.0 | 2. | 1.0 |
3. | 0.5 | 4. | 3.0 |
1. | \(2:1\) | 2. | \(4:9\) |
3. | \(9:4\) | 4. | \(1:2\) |