A ring is made of a wire having a resistance of \(R_0=12~\Omega.\). Find points \(\mathrm{A}\) and \(\mathrm{B}\), as shown in the figure, at which a current-carrying conductor should be connected so that the resistance \(R\) of the subcircuit between these points equals \(\frac{8}{3}~\Omega\)$\mathrm{?}$
      
1. \(\frac{l_1}{l_2} = \frac{5}{8}\)
2. \(\frac{l_1}{l_2} = \frac{1}{3}\)
3. \(\frac{l_1}{l_2} = \frac{3}{8}\)
4. \(\frac{l_1}{l_2} = \frac{1}{2}\)

A wire of resistance \(12~ \Omega \text{m}^{-1}\)${\mathrm{}}^{}$ is bent to form a complete circle of radius \(10~\text{cm}\). The resistance between its two diametrically opposite points, \(A\) and \(B\) as shown in the figure, is:
        
1. \(0.6\pi~\Omega\)$$
2. \(3\pi ~\Omega\)$$
3. \(61 \pi~ \Omega\)$$
4. \(6\pi~\Omega\)$$