A battery of emf 10 V and internal resistance $3 \Omega$ is connected to a resistor. If the current in the circuit is 0.5 A, what is the terminal voltage of the battery when the circuit is closed?

1. 10 V
2. 8.5 V
3. 1.5 V
4. 7.2 V

Three resistors $1 \Omega , 2 \Omega , and 3 \Omega$ are combined in series.  If the combination is connected to a battery of emf 12 V and negligible internal resistance, the potential drop across $2 \Omega$ resistor is:

1. 2 V
2. 5 V
3. 4 V
4. 6 V

Three resistors $2 \Omega , 4\Omega , and 5 \Omega$ are combined in parallel. If the combination is connected to a battery of emf 20 V and negligible internal resistance, the total current drawn from the battery is:

1. 10 A
2. 17 A
3. 13 A
4. 19 A

At room temperature \((27~^\circ \text{C})\) the resistance of a heating element is \(100~\Omega\). What is the temperature of the element if the resistance is found to be \(117~\Omega\)? 
(Given that the temperature coefficient of the material of the resistor is \(1.70\times 10^{-4}~^{\circ}\text{C}^{-1}\))
1. \(1027~^{\circ}\text{C}\)
2. \(1007~^{\circ}\text{C}\)
3. \(1020~^{\circ}\text{C}\)
4. \(1127~^{\circ}\text{C}\)

A negligibly small current is passed through a wire of length \(15~\text{m}\) and uniform cross-section $\mathrm{}$\(6.0\times10^{-7}\) m², and its resistance is measured to be $\mathrm{}$\(5.0~\Omega.\) What is the resistivity of the material at the temperature of the experiment?

A silver wire has a resistance of $2.1 \Omega$ at $27.5 °\mathrm{C}$, and a resistance of $2.7 \Omega$ at $100 °\mathrm{C}$. The temperature coefficient of resistivity of silver is:

1.\(0.0033 \ ^{o}C^{-1}\)
2. \(0.039 \ ^{o}C^{-1}\)
3.\(0.0039 \ ^{o}C^{-1}\)  
4.\(0.033 \ ^{o}C^{-1}\)

The current drawn from a 12 V supply with internal resistance $0.5 \Omega$ by the infinite network (shown in the figure) is:

1. 3.12 A
2. 3.72 A
3. 2.29 A
4. 2.37 A

Figure shows a potentiometer with a cell of 2.0 V and internal resistance 0.40 Ω maintaining a potential drop across the resistor wire AB. A standard cell which maintains a constant emf of 1.02 V (for very moderate currents up to a few mA) gives a balance point at 67.3 cm length of the wire. To ensure very low currents drawn from the standard cell, a very high resistance of 600 kΩ is put in series with it, which is shorted close to the balance point. The standard cell is then replaced by a cell of unknown emf ε and the balance point found similarly, turns out to be at 82.3 cm length of the wire. The value of ε is:

1. 1.33 V
2. 1.50 V
3. 1.24 V
4. 1.07 V

Figure shows a potentiometer circuit for comparison of two resistances. The balance point with a standard resistor R=10.0 Ω is found to be 58.3 cm, while that with the unknown resistance X is 68.5 cm. The value of X is:

1. $12.1\Omega$

2. $12.4 \Omega$

3. $10.3 \Omega$

4. $11.7 \Omega$

The figure shows a 2.0 V potentiometer used for the determination of the internal resistance of a 1.5 V cell. The balance point of the cell in the open circuit is 76.3 cm. When a resistor of 9.5 Ω is used in the external circuit of the cell, the balance point shifts to 64.8 cm length of the potentiometer wire. The internal resistance of the cell is:
    
1. \(1.68~\Omega \)
2. \(0.13~\Omega \)
3. \(0.31~\Omega \)
4. \(1.12~\Omega \)