An electric dipole of moment $$p$$ is placed in an electric field of intensity $$E$$. The dipole acquires a position such that the axis of the dipole makes an angle $$\theta$$ with the direction of the field. Assuming that the potential energy of the dipole to be zero when $$\theta = 90^{\circ},$$ the torque and the potential energy of the dipole will respectively be:

 1 $$p E \sin \theta,-p E \cos \theta$$ 2 $$p E \sin \theta,-2 p E \cos \theta$$ 3 $$p E \sin \theta, 2 p E \cos \theta$$ 4 $$p E \cos \theta,-p E \sin \theta$$
Subtopic:  Energy of Dipole in an External Field |
82%
From NCERT
NEET - 2012
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An electric dipole of moment $$\vec {p}$$ is lying along a uniform electric field $$\vec{E}$$. The work done in rotating the dipole by $$90^{\circ}$$ is:
1. $$\sqrt{2}pE$$
2. $$\frac{pE}{2}$$
3. $$2pE$$
4. $$pE$$

Subtopic:  Energy of Dipole in an External Field |
82%
From NCERT
AIPMT - 2006
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An electric dipole has the magnitude of its charges as q and its dipole moment is p. It is placed in a uniform electric field E. If its dipole moment is along the direction of the field, the force on it and its potential energy are respectively:

 1 q.E and p.E 2 zero and minimum 3 q.E and maximum 4 2q.E and minimum

Subtopic:  Energy of Dipole in an External Field |
77%
From NCERT
AIPMT - 2004
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A short electric dipole has a dipole moment of $$16 \times 10^{-9} ~\text{C-}\text{m}$$. The electric potential due to the dipole at a point at a distance of $$0.6~\text{m}$$ from the centre of the dipole situated on a line making an angle of $$60^{\circ}$$ with the dipole axis is: $$\left( \frac{1}{4\pi \varepsilon_0}= 9\times 10^{9}~\text{N-m}^2/\text{C}^2\right)$$
1. $$200~\text{V}$$
2. $$400~\text{V}$$
3. zero
4. $$50~\text{V}$$

Subtopic:  Energy of Dipole in an External Field |
66%
From NCERT
NEET - 2020
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An electric dipole with dipole moment $\stackrel{\to }{\mathrm{p}}=\left(3\stackrel{^}{i}+4\stackrel{^}{j}\right)×{10}^{-30}$ is placed in an electric field $\stackrel{\to }{\mathrm{E}}=4000\stackrel{^}{i}\left(N/C\right)$. An external agent turns the dipole slowly until its electric dipole moment becomes $\left(-4\stackrel{^}{i}+3\stackrel{^}{j}\right)×{10}^{-30}$ $C-m$. The work done by the external agent is equal to:

1. 4 × 10–28  J

2. –4 × 10–28  J

3. 2.8 × 10–26  J

4. –2.8 × 10–26  J

Subtopic:  Energy of Dipole in an External Field |
From NCERT
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