# In a hydrogen atom, the electron and proton are bound at a distance of about 0.53 Å. The potential energy of the system in eV is: (Taking the zero of the potential energy at an infinite separation of the electron from the proton.) 1. -23.1 eV 2. 27.0 eV 3. -27.2 eV 4. 23.7 eV

Subtopic:  Electric Potential Energy |
67%
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What is the area of the plates of a $$2~\text{F}$$ parallel plate capacitor, given that the separation between the plates is $$0.5~\text{cm}$$?
1. $$1100~\text{km}^2$$
2. $$1130~\text{km}^2$$
3. $$1110~\text{km}^2$$
4. $$1105~\text{km}^2$$

Subtopic:  Capacitance |
72%
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If $$50~\text{J}$$ of work must be done to move an electric charge of $$2~\text{C}$$ from a point where the potential is $$-10$$ volt to another point where the potential is $$\mathrm{V}$$ volt, then the value of $$\mathrm{V}$$ is:
1. $$5$$ volt
2. $$-15$$ volt
3. $$+15$$ volt
4. $$+10$$ volt

Subtopic:  Electric Potential |
84%
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An electric field $\stackrel{\to }{\mathrm{E}}=10x\stackrel{^}{i}$ exists in a certain region of space. Then the potential difference V = Vo– VA, where Vis the potential at the origin and Vis the potential at x = 2 m is:

 1 10 V 2 –20 V 3 +20 V 4 –10 V
Subtopic:  Relation between Field & Potential |
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The increasing order of the electrostatic potential energies for the given system of charges is given by:

 1 a = d < b < c 2 b = d < c < a 3 b = c < a < d 4 c < a < b < d
Subtopic:  Electric Potential |
77%
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Three capacitors A, B and C are connected in a circuit as shown in Fig. What is the charge in $\mathrm{\mu }$C on the capacitor B:

 1 1/3 2 2/3 3 1 4 4/3
Subtopic:  Combination of Capacitors |
57%
From NCERT
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The potential field of an electric field $\mathrm{E}=\left(\mathrm{y}\stackrel{^}{\mathrm{i}}+\mathrm{x}\stackrel{^}{\mathrm{j}}\right)$ is:

 1 V = - x + y + constant 2 V = constant 3 $$\mathrm{V}=-\left(\mathrm{x}^2+\mathrm{y}^2\right)+$$ constant 4 $$V=-x y+$$ constant

Subtopic:  Relation between Field & Potential |
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The capacitance of a parallel plate capacitor with air as a medium is $$6~\mu\text{F}$$. With the introduction of a dielectric medium, the capacitance becomes $$30~\mu\text{F}$$. The permittivity of the medium is:$$\left(\varepsilon_0=8.85 \times 10^{-12} ~\text{C}^2 \text{N}^{-1} \text{m}^{-2}\right )$$

 1 $$1.77 \times 10^{-12}~ \text{C}^2 \text{N}^{-1} \text{m}^{-2}$$ 2 $$0.44 \times 10^{-10} ~\text{C}^2 \text{N}^{-1} \text{m}^{-2}$$ 3 $$5.00 ~\text{C}^2 \text{N}^{-1} \text{m}^{-2}$$ 4 $$0.44 \times 10^{-13} ~\text{C}^2 \text{N}^{-1} \text{m}^{-2}$$

Subtopic:  Dielectrics in Capacitors |
61%
From NCERT
NEET - 2020
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A short electric dipole has a dipole moment of $$16 \times 10^{-9} ~\text{C-}\text{m}$$. The electric potential due to the dipole at a point at a distance of $$0.6~\text{m}$$ from the centre of the dipole situated on a line making an angle of $$60^{\circ}$$ with the dipole axis is: $$\left( \frac{1}{4\pi \varepsilon_0}= 9\times 10^{9}~\text{N-m}^2/\text{C}^2\right)$$
1. $$200~\text{V}$$
2. $$400~\text{V}$$
3. zero
4. $$50~\text{V}$$

Subtopic:  Energy of Dipole in an External Field |
66%
From NCERT
NEET - 2020
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In a certain region of space with volume $$0.2$$ m3, the electric potential is found to be $$5$$ V throughout. The magnitude of electric field in this region is:
1. $$0.5$$ N/C
2. $$1$$ N/C
3. $$5$$ N/C
4. zero

Subtopic:  Relation between Field & Potential |
75%
From NCERT
NEET - 2020
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