A capacitor of capacitance \(C=900~\text{pF}\) is charged fully by \(100~\text{V}\) battery \(B\) as shown in Figure \((a)\). Then it is disconnected from the battery and connected to another uncharged capacitor of capacitance \(C=900~\text{pF}\) as shown in Figure \((b)\). The electrostatic energy stored by the system \((b)\) is:

1. | \(1.5\times 10^{-6}~\text{J}\) | 2. | \(4.5\times 10^{-6}~\text{J}\) |

3. | \(3.25\times 10^{-6}~\text{J}\) | 4. | \(2.25\times 10^{-6}~\text{J}\) |

Subtopic: Â Energy stored in Capacitor |

Â 56%

From NCERT

NEET - 2022

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A parallel plate capacitor has a uniform electric field \(\vec{E}\) in the space between the plates. If the distance between the plates is \(d\) and the area of each plate is \(A\) the energy stored in the capacitor is:

\(\left ( \varepsilon_{0} = \text{permittivity of free space} \right )\)

1. \(\frac{1}{2}\varepsilon_0 E^2 Ad\)

2. \(\frac{E^2 Ad}{\varepsilon_0}\)

3. \(\frac{1}{2}\varepsilon_0 E^2 \)

4. \(\varepsilon_0 EAd\)

Subtopic: Â Energy stored in Capacitor |

Â 71%

From NCERT

NEET - 2021

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Two identical capacitors \(C_{1}\) and \(C_{2}\) of equal capacitance are connected as shown in the circuit. Terminals \(a\) and \(b\) of the key \(k\) are connected to charge capacitor \(C_{1}\) using a battery of emf \(V\) volt. Now disconnecting \(a\) and \(b\) terminals, terminals \(b\) and \(c\) are connected. Due to this, what will be the percentage loss of energy?

1. \(75\%\)

2. \(0\%\)

3. \(50\%\)

4. \(25\%\)

Subtopic: Â Energy stored in Capacitor |

Â 63%

From NCERT

NEET - 2019

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A capacitor is charged by a battery. The battery is removed and another identical uncharged capacitor is connected in parallel. The total electrostatic energy of the resulting system:

1. | \(2\) | decreases by a factor of

2. | remains the same |

3. | \(2\) | increases by a factor of

4. | \(4\) | increases by a factor of

Subtopic: Â Energy stored in Capacitor |

Â 57%

From NCERT

NEET - 2017

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A capacitor of \(2~\mu\text{F}\) is charged as shown in the figure. When the switch \({S}\) is turned to position \(2,\), the percentage of its stored energy dissipated is:

1. \(20\%\)

2. \(75\%\)

3. \(80\%\)

4. \(0\%\)

2. \(75\%\)

3. \(80\%\)

4. \(0\%\)

Subtopic: Â Energy stored in Capacitor |

Â 72%

From NCERT

NEET - 2016

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A parallel plate air capacitor of capacitance \(C\) is connected to a cell of emf \(V\) and then disconnected from it. A dielectric slab of dielectric constant \(K,\) which can just fill the air gap of the capacitor is now inserted in it. Which of the following is incorrect?

1. | the potential difference between the plates decreases \(K\) times. |

2. | the energy stored in the capacitor decreases \(K\) times. |

3. | the change in energy stored is \(\frac{1}{2}CV^{2}\left ( \frac{1}{K} -1\right )\) |

4. | the charge on the capacitor is not conserved. |

Subtopic: Â Energy stored in Capacitor |

Â 71%

From NCERT

NEET - 2015

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A parallel plate capacitor has a uniform electric field \(E\) in the space between the plates. If the distance between the plates is \(d\) and the area of each plate is \(A,\) the energy stored in the capacitor is:

1. \(\frac{E^2 Ad}{\varepsilon_0}\)

2. \(\frac{1}{2}\varepsilon_0E^2 Ad\)

3. \(\varepsilon_0EAd\)

4. \(\frac{1}{2}\varepsilon_0E^2 \)

Subtopic: Â Energy stored in Capacitor |

Â 92%

From NCERT

AIPMT - 2012

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A parallel plate condenser has a uniform electric field \(E\) (V/m) in the space between the plates. If the distance between the plates is \(d\) (m) and the area of each plate is \(A\) (m^{2}), the energy (joule) stored in the condenser is:

1. \( \frac{1}{2}\varepsilon_0{E}^2 \)

2. \( \frac{{E}^2 {Ad}}{\varepsilon_0} \)

3. \( \frac{1}{2}\varepsilon_0 E^2 Ad \)

4. \(\varepsilon_0 EAd \)

Subtopic: Â Energy stored in Capacitor |

Â 90%

From NCERT

NEET - 2021

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A series combination of n_{1} capacitors, each of value C_{1}, is charged by a source of potential difference 4V. When another parallel combination of n_{2} capacitors, each of value C_{2}, is charged by a source of potential difference V, it has the same (total) energy stored in it, as the first combination has. The value of C_{2}, in terms of C_{1}, is then:

1. $\frac{2{C}_{1}}{{n}_{1}{n}_{2}}$

2. $16\frac{{n}_{2}}{{n}_{1}}{C}_{1}$

3. $2\frac{{n}_{2}}{{n}_{1}}{C}_{1}$

4. $\frac{16{C}_{1}}{{n}_{1}{n}_{2}}$

Subtopic: Â Energy stored in Capacitor |

Â 73%

From NCERT

AIPMT - 2010

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Two condensers, one of capacity *\(C\)* and the other of capacity \(\frac{C}2\) are connected to a *\(V\)* volt battery, as shown in the figure.

The energy stored in the capacitors when both condensers are fully charged will be:

1. \(2CV^2\)

2. \({1 \over4}CV^2\)

3. \({3 \over4}CV^2\)

4. \({1 \over2}CV^2\)

Subtopic: Â Energy stored in Capacitor |

Â 83%

From NCERT

AIPMT - 2007

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