The capacitance of a parallel plate capacitor with air as a medium is $$6~\mu\text{F}$$. With the introduction of a dielectric medium, the capacitance becomes $$30~\mu\text{F}$$. The permittivity of the medium is:$$\left(\varepsilon_0=8.85 \times 10^{-12} ~\text{C}^2 \text{N}^{-1} \text{m}^{-2}\right )$$

 1 $$1.77 \times 10^{-12}~ \text{C}^2 \text{N}^{-1} \text{m}^{-2}$$ 2 $$0.44 \times 10^{-10} ~\text{C}^2 \text{N}^{-1} \text{m}^{-2}$$ 3 $$5.00 ~\text{C}^2 \text{N}^{-1} \text{m}^{-2}$$ 4 $$0.44 \times 10^{-13} ~\text{C}^2 \text{N}^{-1} \text{m}^{-2}$$

Subtopic:  Dielectrics in Capacitors |
61%
From NCERT
NEET - 2020
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A parallel plate capacitor with cross-sectional area $$A$$ and separation $$d$$ has air between the plates. An insulating slab of the same area but the thickness of $$\frac{d}{2}$$ is inserted between the plates as shown in the figure having a dielectric constant, $$K=4$$. The ratio of new capacitance to its original capacitance will be:

 1 $$2:1$$ 2 $$8:5$$ 3 $$6:5$$ 4 $$4:1$$
Subtopic:  Dielectrics in Capacitors |
74%
From NCERT
NEET - 2020
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A parallel-plate capacitor of area $$A$$, plate separation $$d$$ and capacitance $$C$$ is filled with four dielectric materials having dielectric constants $$k_1, k_2,k_3$$ and $$k_4$$ as shown in the figure below. If a single dielectric material is to be used to have the same capacitance $$C$$ in this capacitor, then its dielectric constant $$k$$ is given by:

1. $${k}={k}_1+{k}_2+{k}_3+3 {k}_4$$
2. $${k}=\frac{2}{3}\left({k}_1+{k}_2+{k}_3\right)+2 {k}_4$$
3. $${k}=\frac{2}{3} {k}_4\left(\frac{{k}_1}{{k}_1+{K}_4}+\frac{{k}_2}{{k}_2+{k}_4}+\frac{{k}_3}{{k}_3+{k}_4}\right)$$
4. $$\frac{1}{{k}}=\frac{1}{{k}_1}+\frac{1}{{k}_2}+\frac{1}{{k}_3}+\frac{3}{2 {k}_4}$$

Subtopic:  Dielectrics in Capacitors |
62%
From NCERT
NEET - 2016
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Two thin dielectric slabs of dielectric constants $$K_1$$ and $$K_2$$ $$(K_1<K_2)$$ are inserted between plates of a parallel plate capacitor, as shown in the figure. The variation of electric field $$'E'$$ between the plates with distance $$'d'$$ as measured from the plate $$P$$ is correctly shown by:

 1 2 3 4
Subtopic:  Dielectrics in Capacitors |
77%
From NCERT
AIPMT - 2014
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Two parallel metal plates having charges +Q and –Q, face each other at a certain distance between them. If the plates are now dipped in the kerosene oil tank, the electric field between the plates will:

 1 increase. 2 decrease. 3 remain the same. 4 become zero.
Subtopic:  Dielectrics in Capacitors |
77%
From NCERT
AIPMT - 2010
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