The energy and capacity of a charged parallel plate capacitor are \(E\) and \(C\) respectively. If a dielectric slab of \(E_r=6\) is inserted in it, then the energy and capacity become:
(Assuming the charge on plates remains constant)
1. \(6 E,6 C\) 2. \( E,C\)
3. \(\frac{E}{6},6C\) 4. \(E,6C\)
Subtopic:  Energy stored in Capacitor |
 76%
From NCERT
AIPMT - 1999
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Energy per unit volume for a capacitor having area \(A\) and separation \(d\) kept at a potential difference \(V\) is given by:

1. \(\dfrac{1}{2}\varepsilon_0\dfrac{V^2}{d^2}\) 2. \(\dfrac{1}{2}\dfrac{V^2}{\varepsilon_0d^2}\)
3. \(\dfrac{1}{2}CV^2\) 4. \(\dfrac{Q^2}{2C}\)
Subtopic:  Energy stored in Capacitor |
 82%
From NCERT
AIPMT - 2001
To view explanation, please take trial in the course.
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To view explanation, please take trial in the course.
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