- 1(current)
Q. No.When a particle with charge \(+q\) is thrown with an initial velocity \(v\) towards another stationary change \(+Q,\) it is repelled back after reaching the nearest distance \(r\) from \(+Q.\) The closest distance that it can reach if it is thrown with an initial velocity \(2v,\) is:
| 1. | \(\frac{r}{4}\) | 2. | \(\frac{r}{2}\) |
| 3. | \(\frac{r}{16}\) | 4. | \(\frac{r}{8}\) |
Subtopic: Â Electric Potential Energy |
 67%
From NCERT
NEET - 2022
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NEET 2023 - Target Batch - Aryan Raj Singh
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NEET 2023 - Target Batch - Aryan Raj Singh
Six charges \(+q,\) \(-q,\) \(+q,\) \(-q,\) \(+q\) and \(-q\) are fixed at the corners of a hexagon of side \(d\) as shown in the figure. The work done in bringing a charge \(q_0\) to the centre of the hexagon from infinity is:
(\(\varepsilon_0-\)permittivity of free space)
1. zero
2. \(\frac{-q^2}{4\pi\varepsilon_0d}\)
3. \(\frac{-q^2}{4\pi\varepsilon_0d}\Big(3-\frac{1}{\sqrt2}\Big)\)
4. \(\frac{-q^2}{4\pi\varepsilon_0d}\Big(6-\frac{1}{\sqrt2}\Big)\)
(\(\varepsilon_0-\)permittivity of free space)
1. zero
2. \(\frac{-q^2}{4\pi\varepsilon_0d}\)
3. \(\frac{-q^2}{4\pi\varepsilon_0d}\Big(3-\frac{1}{\sqrt2}\Big)\)
4. \(\frac{-q^2}{4\pi\varepsilon_0d}\Big(6-\frac{1}{\sqrt2}\Big)\)
Subtopic: Â Electric Potential Energy |
 82%
From NCERT
NEET - 2022
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
Hints
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
- 1(current)
Q. No.
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