- 1(current)
Q. No.The mean free path of molecules in an ideal gas \(A\) is half that of another ideal gas \(B.\) The diameter of the spherical molecules of gas \(A\) is twice the diameter of the molecules of \(B.\) If number densities of the gases \(A\) and \(B\) are \(n_A\) and \(n_B\), respectively, then the correct option is:
1. \(n_A = \dfrac{1}{2} n_B\)
2. \(n_A = n_B~\)
3. \(n_A = 2 n_B\)
4. \(n_A = \dfrac{1}{4} n_B\)
1. \(n_A = \dfrac{1}{2} n_B\)
2. \(n_A = n_B~\)
3. \(n_A = 2 n_B\)
4. \(n_A = \dfrac{1}{4} n_B\)
Subtopic: Â Mean Free Path |
Level 3: 35%-60%
NEET - 2026
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Please attempt this question first.
The mean free path for a gas, with molecular diameter \(d\) and number density \(n,\) can be expressed as:
| 1. | \( \dfrac{1}{\sqrt{2} n \pi {d}^2} \) | 2. | \( \dfrac{1}{\sqrt{2} n^2 \pi {d}^2} \) |
| 3. | \(\dfrac{1}{\sqrt{2} n^2 \pi^2 d^2} \) | 4. | \( \dfrac{1}{\sqrt{2} n \pi {d}}\) |
Subtopic: Â Mean Free Path |
 84%
Level 1: 80%+
NEET - 2020
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The mean free path \(l\) for a gas molecule depends upon the diameter, \(d\) of the molecule as:
| 1. | \(l\propto \dfrac{1}{d^2}\) | 2. | \(l\propto d\) |
| 3. | \(l\propto d^2 \) | 4. | \(l\propto \dfrac{1}{d}\) |
Subtopic: Â Mean Free Path |
 86%
Level 1: 80%+
NEET - 2020
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- 1(current)
Q. No.
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