A thermodynamic system undergoes a cyclic process \(ABCDA\) as shown in Fig. The work done by the system in the cycle is: 
             
1. \( P_0 V_0 \)
2. \( 2 P_0 V_0 \)
3. \( \frac{P_0 V_0}{2} \)
4. zero

Subtopic:  Cyclic Process |
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AIPMT - 2014
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In the cyclic process shown in the pressure-volume \((P-V)\) diagram, the change in internal energy is equal to:

     

1. πP2-P122

2. πV2-V122

3. π4(P2-P1)(V2-V1)

4. zero

Subtopic:  Cyclic Process |
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ABCA is a cyclic process. Its P-V graph would be:

   

1. 2.
3. 4.
Subtopic:  Cyclic Process |
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For the indicator diagram given below, which of the following is not correct?

                         

1. Cycle - II is a heat engine cycle.
2. Net work is done on the gas in cycle I.
3. Work done is positive for cycle I.
4. Work done is positive for cycle II.

Subtopic:  Cyclic Process |
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In the P-V diagram shown, the gas does 5 J of work in the isothermal process ab and 4 J in the adiabatic process bc. What will be the change in internal energy of the gas in the straight path from c to a? 


1. 9J 

2. 1 J

3. 4 J 

4. 5 J

Subtopic:  Cyclic Process |
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In a cyclic process, the internal energy of the gas:

1. Increases 2. Decreases
3. Remains constant 4. Becomes zero
Subtopic:  Cyclic Process |
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