- 1(current)
Q. No.In this \((P-V)\) diagram below the dashed curved line is adiabatic.
For a process, that is described by a straight line joining two points \(X\) and \(Y\) on the adiabat (solid line In the diagram) heat is:
(Consider the variations in temperature from \(X\) to \(Y\) along the straight line.)
| 1. | absorbed throughout from \(X\) to \(Y.\) |
| 2. | released throughout from \(X\) to \(Y.\) |
| 3. | absorbed from \(X\) up to an intermediate point \(Z\) (not shown In the figure) and then released from \(Z\) to \(Y.\) |
| 4. | released from \(X\) up to an Intermediate point \(Z\) (not shown in the figure) and then absorbed from \(Z\) to \(Y.\) |
| 1. | \(4\) | 2. | \(1\) |
| 3. | \(2\) | 4. | \(3\) |
Match the thermodynamic processes taking place in a system with the correct conditions. In the table, Q is the heat supplied, W is the work done and U is the change in internal energy of the system.
| Process | Condition | ||
| (I) | Adiabatic | (A) | \(\Delta W=0\) |
| (II) | Isothermal | (B) | \(\Delta Q=0\) |
| (III) | Isochoric | (C) | \(\Delta U\neq0, \Delta W\neq0,\Delta Q\neq0\) |
| (IV) | Isobaric | (D) | \(\Delta U=0\) |
| 1. | (I) – (B), (II) – (A), (III) – (D), (IV) – (C) |
| 2. | (I) – (A), (II) – (A), (III) – (B), (IV) – (C) |
| 3. | (I) – (A), (II) – (B), (III) – (D), (IV) – (D) |
| 4. | (I) – (B), (II) – (D), (III) – (A), (IV) – (C) |
Thermodynamic processes are indicated in the following diagram:
Match the following:
| Column-I | Column-II | ||
| P. | Process I | a. | Adiabatic |
| Q. | Process II | b. | Isobaric |
| R. | Process III | c. | Isochoric |
| S. | Process IV | d. | Isothermal |
| P | Q | R | S | |
| 1. | c | a | d | b |
| 2. | c | d | b | a |
| 3. | d | b | a | c |
| 4. | a | c | d | b |
Figure shows P-T diagram for given mass of an ideal gas for the process A→B. During this process, density of the gas is
1. Decreasing
2. Increasing
3. Constant
4. First decreasing then increasing
- 1(current)
Q. No.
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