On a new scale of temperature, which is linear and called the \(\text{W}\) scale, the freezing and boiling points of water are \(39^\circ ~\text{W}\) and \(239^\circ ~\text{W}\) respectively. What will be the temperature on the new scale corresponding to a temperature of \(39^\circ ~\text{C}\) on the Celsius scale?
1. \(78^\circ ~\text{W}\)
2. \(117^\circ ~\text{W}\)
3. \(200^\circ ~\text{W}\)
4. \(139^\circ ~\text{W}\)

Subtopic:  Temperature and Heat |
 85%
From NCERT
AIPMT - 2008
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Two absolute scales \(A \) and \(B,\) have triple points of water defined to be \(200 A\) and \(350 B.\) The relationship between \(T_A \) and \(T_B\) is:
1. \(T_A = \dfrac{5}{7}T_B\)

2. \(T_A = \dfrac{4}{7}T_B\)

3. \(T_A = \dfrac{6}{7}T_B\)

4. \(T_A = T_B\)
Subtopic:  Temperature and Heat |
 74%
From NCERT
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The temperature of a body on the Kelvin scale is found to be \(x^\circ~\text K.\) When it is measured by a Fahrenheit thermometer, it is found to be \(x^\circ~\text F,\) then the value of \(x\) is:
1. \(40\)

2. \(313\)

3. \(574.25\)

4. \(301.25\)

Subtopic:  Temperature and Heat |
 74%
From NCERT
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