The power radiated by a black body is \(P\) and it radiates maximum energy at wavelength \(\lambda_0.\) Temperature of the black body is now changed so that it radiates maximum energy at the wavelength \(\dfrac{3}{4}\lambda_0.\) The power radiated by it now becomes \(nP.\) The value of \(n\) is:

1. \( \dfrac{3}{4} \) 2. \( \dfrac{4}{3} \)
3. \( \dfrac{256}{81} \) 4. \( \dfrac{81}{256}\)
Subtopic:  Wien's Displacement Law |
 67%
From NCERT
NEET - 2018
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A black body is at a temperature of \(5760~\text{K}.\) The energy of radiation emitted by the body at wavelength \(250~\text{nm}\) is \(U_1,\) at wavelength \(500~\text{nm}\) is \(U_2\) and that at \(1000~\text{nm}\) is \(U_3.\) Wien’s constant, \(b=2.88 \times 10^6~ \text{nm-K}.\) Which of the following is correct?
1. \({U}_3 =0 \)
2. \({U}_1 >{U}_2 \)
3. \({U}_2 >{U}_1 \)
4. \({U}_1 =0\)
Subtopic:  Wien's Displacement Law |
 63%
From NCERT
NEET - 2016
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