The power radiated by a black body is $$P$$ and it radiates maximum energy at wavelength ${}_{}$$$\lambda_0$$. Temperature of the black body is now changed so that it radiates maximum energy at the wavelength $$\frac{3}{4}\lambda_0$$. The power radiated by it now becomes $$nP$$. The value of $$n$$ is:
1. $$\frac{3}{4}$$
2. $$\frac{4}{3}$$
3. $$\frac{256}{81}$$
4. $$\frac{81}{256}$$

Subtopic:  Wien's Displacement Law |
65%
From NCERT
NEET - 2018
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A black body is at a temperature of $$5760~\mathrm{K}$$. The energy of radiation emitted by the body at wavelength $$250~\mathrm{nm}$$ is $$U_1$$, at wavelength $$500~\mathrm{nm}$$ is $$U_2$$ and that at $$1000~\mathrm{nm}$$ is $$U_3$$. Wien’s constant, $$\mathrm{b}=2.88 \times 10^6 \mathrm{~nm}-\mathrm{K}$$. Which of the following is correct?
1. $$\mathrm{U}_3 =0$$
2. $$\mathrm{U}_1 >\mathrm{U}_2$$
3. $$\mathrm{U}_2 >\mathrm{U}_1$$
4. $$\mathrm{U}_1 =0$$
Subtopic:  Wien's Displacement Law |
64%
From NCERT
NEET - 2016
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