In a vernier callipers, $$(N+1)$$ divisions of the vernier scale coincide with $$N$$ divisions of the main scale. If $$1$$ $$\text{MSD}$$ represents $$0.1~\text{mm}$$, the vernier constant (in $$\text{cm}$$) is:
 1 $$\dfrac{1}{100(N+1)}$$ 2 $$100N$$ 3 $$10(N+1)$$ 4 $$\dfrac{1}{10 N}$$
Subtopic: Â Measurement & Measuring Devices |
Â 73%
From NCERT
NEET - 2024
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A vernier calipers has $$1~\text{mm}$$ marks on the main scale. It has $$20$$ equal divisions on the vernier scale which match with $$16$$ main scale divisions. The least count of this vernier calipers is:
1. $$0.02~\text{mm}$$
2. $$0.05~\text{mm}$$
3. $$0.10~\text{mm}$$
4. $$0.20~\text{mm}$$
Subtopic: Â Measurement & Measuring Devices |
Â 64%
From NCERT
NEET - 2024
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The diameter of a spherical bob, when measured with vernier callipers yielded the values: $$3.33$$ cm, $$3.32$$ cm, $$3.34$$ cm, $$3.33$$ cm and $$3.32$$ cm. The mean diameter to appropriate significant figures is:
1. $$3.328$$ cm
2. $$3.3$$ cm
3. $$3.33$$ cm
4. $$3.32$$ cm
Subtopic: Â Measurement & Measuring Devices |
Â 55%
From NCERT
NEET - 2023
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When the circular scale of a screw gauge completes $$2$$ rotations, it covers $$1$$ mm over the pitch scale. The total number of circular scale divisions is $$50$$. The least count of the screw gauge in metres is:
1. $$10^{-4}$$
2. $$10^{-5}$$
3. $$10^{-2}$$
4. $$10^{-3}$$

Subtopic: Â Measurement & Measuring Devices |
Â 55%
From NCERT
NEET - 2022
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A screw gauge has the least count of $$0.01~\text{mm}$$ and there are $$50$$ divisions in its circular scale. The pitch of the screw gauge is:
1. $$0.25$$ mm
2. $$0.5$$ mm
3. $$1.0$$ mm
4. $$0.01$$ mm

Subtopic: Â Measurement & Measuring Devices |
Â 84%
From NCERT
NEET - 2020
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The angle of $$1'$$ (minute of an arc) in radian is nearly equal to:
1. $$2.91 \times 10^{-4} ~\mathrm{rad}$$
2. $$4.85 \times 10^{-4} ~\mathrm{rad}$$
3. $$4.80 \times 10^{-6} ~\mathrm{rad}$$
4. $$1.75 \times 10^{-2} ~\mathrm{rad}$$

Subtopic: Â Measurement & Measuring Devices |
Â 53%
From NCERT
NEET - 2020
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The main scale of a vernier calliper has $$n$$ divisions/cm. $$n$$ divisions of the vernier scale coincide with $$(n-1)$$ divisions of the main scale. The least count of the vernier calliper is:
1. $$\frac{1}{(n+1)(n-1)}$$ cm
2. $$\frac{1}{n}$$ cm
3. $$\frac{1}{n^{2}}$$ cm
4. $$\frac{1}{(n)(n+1)}$$ cm

Subtopic: Â Measurement & Measuring Devices |
Â 50%
From NCERT
NEET - 2019
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