- 1(current)
Q. No.Considering the formation, breaking and strength of hydrogen bond, predict which of the following mixtures will show a positive deviation from Raoult’s law?
1. Methanol and acetone
2. Chloroform and acetone
3. Nitric acid and water
4. Phenol and aniline
On the basis of the information given below mark the correct option.
Information
| i. | In bromoethane and chloroethane mixture intermolecular interactions of A—A and B—B type are nearly the same as A—B type interactions. |
| ii. | In ethanol and acetone mixture A—A or B—B type intermolecular interactions are stronger than A—B type interactions. |
| iii. | In chloroform and acetone mixture A—A or B—B type intermolecular interactions are weaker than A—B type interactions. |
1. Solution (ii) and (iii) will follow Raoult’s law
2. Solution (i) will follow Raoult’s law
3. Solution (ii) will show negative deviation from Raoult’s law
4. Solution (iii) will show positive deviation from Raoult’s law
If two liquids A and B form minimum boiling azeotrope at some specific composition then
| 1. | A—B interactions are stronger than those between A—A or B—B |
| 2. | Vapour pressure of solution increases because more number of molecules of liquids A and B can escape from the solution |
| 3. | Vapour pressure of solution decreases because less number of molecules of only one of the liquids escape from the solution |
| 4. | A—B interactions are weaker than those between A—A or B—B |
Information: Some hydrogen bonds between methanol molecules are disrupted after adding acetone to methanol.
Select the appropriate option:
| 1. | At specific compositions, a methanol-acetone mixture will form a minimum boiling azeotrope and show a positive deviation from Raoult’s law. |
| 2. | At specific compositions, a methanol-acetone mixture will form a maximum boiling azeotrope and show a positive deviation from Raoult’s law. |
| 3. | At specific compositions, a methanol-acetone mixture will form a minimum boiling azeotrope and show a negative deviation from Raoult’s law. |
| 4. | At specific compositions, a methanol-acetone mixture will form maximum boiling azeotrope and show a negative deviation from Raoult’s law. |
The strength of intermolecular forces between two benzene molecules is approximately equivalent to that between two toluene molecules.
| a. | ΔHmix= zero |
| b. | ΔVmix = Zero |
| c. | They will form a minimum boiling azeotrope |
| d. | They will not form an ideal solution |
Identify the incorrect statements (from a to d given above) regarding a mixture of benzene and toluene:
1. (a, b)
2. (b, c)
3. (c, d)
4. (a, d)
Which of the following binary mixtures will have the same composition in the liquid and vapour phase?
a. Benzene-toluene
b. Water-nitric acid
c. Water-ethanol
d. n-Hexane-n-heptane
The correct choice among the given is -
1. (a, b)
2. (b, c)
3. (c, d)
4. (a, d)
- 1(current)
Q. No.
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