1.00 g of non-electrolyte solute (molar mass 250 g mol^-1) was dissolved in 51.2 g of benzene. If the freezing point depression constant, K_f of benzene is 5.12 mol^-1 kg K, the freezing point of benzene will be lowered by:

1. 0.4 K

2. 0.3 K

3. 0.5 K

4. 0.2 K

A solution that has the highest boiling point among the following is -

1. 1.0 M NaOH

2. 1.0 M Na₂SO₄ 

3. 1.0 M NH₄NO₃

4. 1.0 M KNO₃

A solution containing 3.3 g of a substance in 125 g of benzene (b.p. 80 °C) boils at 80.66 °C. If K_b for one litre of benzene is 3.28 °C m^-1, the molecular weight of the substance shall be -

1. 127.20 g mol^-1

2. 131.20 g mol^-1

3. 137.12 g mol^-1

4. 142.72 g mol^-1

The unit of Ebullioscopic constant is:

1. K kg mol^-1 or K (molality)^-1

2. mol kg K^-1 or K^-1 (molality)

3. kg mol^-1 K^-1 or K^-1 (molality)^-1

4. K mol kg^-1 or K (molality)

The correct graph amongst the following, that represents the elevation in boiling point is:

1.
2.
3.
4.	None of the above.

The boiling point of 0.2 mol kg^-1 solution of X in water is greater than the equimolal solution of Y in water. The correct statement in this case is:

Aluminium phosphate is 100 % ionized in 0.01 m aqueous solution. Hence, $∆{\mathrm{T}}_{\mathrm{b}}/{\mathrm{k}}_{\mathrm{b}}$ is-

The lowest boiling point, if concentration is fixed at 0.1 M in aqueous solution, is given by which of the following solutions?

a. K₂SO₄

b. NaCl

c. Urea

d. Glucose

1. a, b

2. b, c

3. c, d

4. d, a

The latent heat of vaporization of water is 540 cal g^-1 at 100 ^oC. K_b for water is:

1. $0.562 \mathrm{K }{m}^{-1}$

2. $1.86 \mathrm{K }{m}^{-1}$

3. $0.515 \mathrm{K }{m}^{-1}$

4. $5.12 \mathrm{K }{m}^{-1}$