Which of the following is true, when \(5\) moles of liquid \(\text X\) and \(10\) moles of liquid \(\text Y\) make a solution having a vapour pressure of \(70\) torr?
[Given: The vapour pressures of pure \(\text X\) and \(\text Y\) are \(63\) torr and \(78\) torr respectively]
1. The solution is ideal. 
2. The solution has a volume that is greater than the sum of individual volumes. 
3. The solution shows positive deviation. 
4. The solution shows negative deviation. 
Subtopic:  Raoult's Law |
 55%
Level 3: 35%-60%
NEET - 2025
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The correct option for the value of vapour pressure of a solution at 45 °C with benzene to octane in a molar ratio 3:2 is:

[At 45 °C vapour pressure of benzene is 280 mm Hg and that of octane is 420 mm Hg. Assume Ideal gas]

1. 336 mm of Hg 2. 350 mm of Hg
3. 160 mm of Hg 4. 168 mm of Hg
Subtopic:  Raoult's Law |
 76%
Level 2: 60%+
NEET - 2021
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The mixture that shows positive deviation from Raoult's law is:

1. Benzene + Toluene

2. Acetone + Chloroform

3. Chloroethane + Bromoethane

4. Ethanol + Acetone

Subtopic:  Raoult's Law |
 69%
Level 2: 60%+
NEET - 2020
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For an ideal solution, the correct option is:

1. mix G=0 at constant T and P

2. mix S=0 at constant T and P

3. mix V0 at constant T and P

4. mix H=0 at constant T and P

Subtopic:  Raoult's Law |
 83%
Level 1: 80%+
NEET - 2019
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The correct statement regarding a solution of two components A and B exhibiting positive deviation from ideal behaviour is :

1. Intermolecular attractive force between A-A and B-B are stronger than those between A-B
2. mixH = 0 at constant T and P
3. mixV = 0 at constant T and P
4. Intermolecular attractive forces between A-A and B-B are equal to those between A-B
Subtopic:  Raoult's Law |
 86%
Level 1: 80%+
NEET - 2019
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