\(5\) moles of liquid \(\text X\) and \(10\) moles of liquid \(\text Y\) make a solution having a vapour pressure of \(70\) torr. The vapour pressures of pure \(\text X\) and \(\text Y\) are \(63\) torr and \(78\) torr respectively. Which of the following is true regarding the described solution? 
 
1. The solution is ideal. 
2. The solution has volume greater than the sum of individual volumes. 
3. The solution shows positive deviation. 
4. The solution shows negative deviation. 
Subtopic:  Raoult's Law |
 51%
From NCERT
NEET - 2025
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The correct option for the value of vapour pressure of a solution at 45 °C with benzene to octane in a molar ratio 3:2 is:

[At 45 °C vapour pressure of benzene is 280 mm Hg and that of octane is 420 mm Hg. Assume Ideal gas]
1. 336 mm of Hg
2. 350 mm of Hg
3. 160 mm of Hg
4. 168 mm of Hg

Subtopic:  Raoult's Law |
 75%
From NCERT
NEET - 2021
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The mixture that shows positive deviation from Raoult's law is-

1. Benzene + Toluene

2. Acetone + Chloroform

3. Chloroethane + Bromoethane

4. Ethanol + Acetone

Subtopic:  Raoult's Law |
 69%
From NCERT
NEET - 2020
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For an ideal solution, the correct option is:

1. mix G=0 at constant T and P

2. mix S=0 at constant T and P

3. mix V0 at constant T and P

4. mix H=0 at constant T and P

Subtopic:  Raoult's Law |
 82%
From NCERT
NEET - 2019
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The correct statement regarding a solution of two components A and B exhibiting positive deviation from ideal behaviour is :

1. Intermolecular attractive force between A-A and B-B are stronger than those between A-B
2. mixH = 0 at constant T and P
3. mixV = 0 at constant T and P
4. Intermolecular attractive forces between A-A and B-B are equal to those between A-B
Subtopic:  Raoult's Law |
 86%
From NCERT
NEET - 2019
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