- 1(current)
Q. No.The quantum numbers of four electrons are given below:
A. \(n\)=3; \(l\)=2; \(m_l\)=1; and s=+\(\frac1{2}\)
B. \(n\)=4; \(l\)=1; \(m_l\)=0; and s=+\(\frac1{2}\)
C. \(n\)=4; \(l\)=2; \(m_l\)=-2; and s=-\(\frac1{2}\)
D. \(n\)=3; \(l\)=1; \(m_l\)=-1; and s=+\(\frac1{2}\)
The correct decreasing order of energy of these electrons is:
1. C>A>B>D
2. C>B>A>D
3. C>D>A>B
4. A>C>D>B
A. \(n\)=3; \(l\)=2; \(m_l\)=1; and s=+\(\frac1{2}\)
B. \(n\)=4; \(l\)=1; \(m_l\)=0; and s=+\(\frac1{2}\)
C. \(n\)=4; \(l\)=2; \(m_l\)=-2; and s=-\(\frac1{2}\)
D. \(n\)=3; \(l\)=1; \(m_l\)=-1; and s=+\(\frac1{2}\)
The correct decreasing order of energy of these electrons is:
1. C>A>B>D
2. C>B>A>D
3. C>D>A>B
4. A>C>D>B
Subtopic: Â Pauli's Exclusion Principle & Hund's Rule |Â AUFBAU Principle |
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NEET - 2024
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