The mole fraction of the solute in a 1.00 molal aqueous solution is:
| 1. | 0.00177 | 2. | 0.0344 |
| 3. | 0.0177 | 4. | 0.1770 |
Find the mass of CaCO₃ required to completely react with 25 mL of 0.75 M HCl according to the reaction:
CaCO₃(s) + 2HCl(aq) → CaCl₂(aq) + CO₂(g) + H₂O(l)
1. 0.36 g
2. 0.09 g
3. 0.96 g
4. 0.66 g
An aqueous solution of NaOH has a molarity of 2 M and a density of 1.28 g cm⁻³.
Calculate the molality of the solution:
[Given: Molecular mass of NaOH = 40 g mol-1]
| 1. | 1.20 m | 2. | 1.56 m |
| 3. | 1.67 m | 4. | 1.32 m |
Concentrated nitric acid is 70% HNO3. The amount of concentrated nitric acid solution that should be used to prepare 250 mL of 2.0 M HNO3 would be:
1. 90.0 g conc. HNO3
2. 70.0 g conc. HNO3
3. 54.0 g conc. HNO3
4. 45.0 g conc. HNO3
A solution is prepared by adding 2 g of substance A to 18 g of water. The mass percent of the solute is:
1. 20%
2. 10%
3. 15%
4. 18%
An aqueous solution contains 18 g of urea in 1500 cm³ of solution.
If the density of the solution is 1.052 g cm⁻³ and the molar mass of urea is 60 g mol⁻¹,
calculate the molality of the solution.
1. 0.2
2. 0.192
3. 0.064
4. 1.2
Sulphuric acid reacts with sodium hydroxide according to the reaction:
When 1L of 0.1 M sulphuric acid solution is allowed to react with 1 L of 0.1 M sodium hydroxide solution, the amount of sodium sulphate formed and its molarity in the solution obtained are respectively-
| 1. | 0.1 M, 7.10 g | 2. | 7.10 g, 0.025 M |
| 3. | 0.025 M, 3.55 g | 4. | 3.55 g, 0.25 M |
Find the mass of NaNO₃ required to prepare 50 mL of aqueous solution containing 70.0 mg Na⁺ per mL.
(Round off to the nearest integer.
Given: Na = 23, N = 14, O = 16)
| 1. | 13 g | 2. | 26 g |
| 3. | 18 g | 4. | 22 g |