The mole fraction of the solute in a 1.00 molal aqueous solution is: 

1. 0.00177 2. 0.0344
3. 0.0177 4. 0.1770
Subtopic:  Concentration Based Problem |
Level 3: 35%-60%
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Find the mass of CaCO₃ required to completely react with 25 mL of 0.75 M HCl according to the reaction:

CaCO₃(s) + 2HCl(aq) → CaCl₂(aq) + CO₂(g) + H₂O(l)

 

1. 0.36 g

2. 0.09 g

3. 0.96 g

4. 0.66 g

Subtopic:  Concentration Based Problem | Equation Based Problem |
 65%
Level 2: 60%+
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An aqueous solution of NaOH has a molarity of 2 M and a density of 1.28 g cm⁻³.
Calculate the molality of the solution:
[Given: Molecular mass of NaOH = 40 g mol-1]

1. 1.20 m 2. 1.56 m
3. 1.67 m 4. 1.32 m
Subtopic:  Concentration Based Problem |
 74%
Level 2: 60%+
NEET - 2019
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Concentrated nitric acid is 70% HNO3. The amount of concentrated nitric acid solution that should be used to prepare 250 mL of 2.0 M HNO3 would be:

1. 90.0 g conc. HNO3
2. 70.0 g conc. HNO3
3. 54.0 g conc. HNO3
4. 45.0 g conc. HNO3

Subtopic:  Concentration Based Problem |
Level 4: Below 35%
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A solution is prepared by adding 2 g of substance A to 18 g of water. The mass percent of the solute is:

1. 20%

2. 10%

3. 15%

4. 18%

Subtopic:  Concentration Based Problem |
 85%
Level 1: 80%+
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An aqueous solution contains 18 g of urea in 1500 cm³ of solution.
If the density of the solution is 1.052 g cm⁻³ and the molar mass of urea is 60 g mol⁻¹,
calculate the molality of the solution.
1. 0.2
2. 0.192
3. 0.064
4. 1.2

Subtopic:  Concentration Based Problem |
 67%
Level 2: 60%+
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Sulphuric acid reacts with sodium hydroxide according to the reaction:

H2SO4+2NaOHNa2SO4+2H2O

When 1L of 0.1 M sulphuric acid solution is allowed to react with 1 L of 0.1 M sodium hydroxide solution, the amount of sodium sulphate formed and its molarity in the solution obtained are respectively-

1. 0.1 M, 7.10 g 2. 7.10 g, 0.025 M
3. 0.025 M, 3.55 g 4. 3.55 g, 0.25 M
Subtopic:  Concentration Based Problem |
 59%
Level 3: 35%-60%
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Find the mass of NaNO₃ required to prepare 50 mL of aqueous solution containing 70.0 mg Na⁺ per mL.
(Round off to the nearest integer.
Given: Na = 23, N = 14, O = 16)

1. 13 g 2. 26 g
3. 18 g 4. 22 g
Subtopic:  Concentration Based Problem |
 54%
Level 3: 35%-60%
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