The mass of CO2 produced by heating 20 g of 20% pure limestone, as per the equation given below, is:\(\mathrm{CaCO}_3(\mathrm{~s}) \xrightarrow{\text { heat }} \mathrm{CaO}(s)+\mathrm{CO}_2(\mathrm{~g})\)
1.
1.32 g
2.
1.12 g
3.
1.76 g
4.
2.64 g
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Subtopic: Equation Based Problem |
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Level 2: 60%+
NEET - 2023
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Calculate the mass of 95% pure CaCO3 that will be required to neutralize 50 mL of 0.5 M HCl solution according to the following reaction.
CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + 2H2O(l)
[Calculate up to the second place of decimal point]
1.
9.50 g
2.
1.25 g
3.
1.32 g
4.
3.65 g
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Subtopic: Equation Based Problem |
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Level 3: 35%-60%
NEET - 2022
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