In a mildly alkaline medium, thiosulphate ion is oxidized by MnO4- to "A". The oxidation state of sulphur in "A" is:

1. +4 2. +2
3. –2 4. +6

Subtopic:  d-Block Elements- Properties & Uses |
 65%
From NCERT
JEE
Please attempt this question first.
Hints
Please attempt this question first.

In basic medium CrO42− oxidizes S2O32– to form S2O32−  to form  SO42−  and itself changes into Cr(OH)4 . The volume of 0.154 M  CrO42− required to react with 40 mL of 0.25 M S2O32− is: 

(Rounded-off to the nearest integer)

1. 178 
2. 173 
3. 169 
4. 181

Subtopic:  d-Block Elements- Properties & Uses |
JEE
Please attempt this question first.
Hints

What is the outer electronic configuration of Gadolinium (\(Gd\)) with atomic number 64?

1.  \(4 f^3~ 5 d^5~ 6 s^2\)

2.  \(4 f^8~ 5 d^0 ~6 s^2\)

3. \(4 f^4~ 5 d^4~ 6 s^2\)

4.  \(4 f^7~ 5 d^1~ 6 s^2\)

Subtopic:  d-Block Elements- Properties & Uses |
 89%
From NCERT
JEE
Please attempt this question first.
Hints
Please attempt this question first.

advertisementadvertisement

In context with the transition elements, which of the following statements is incorrect?

1. In addition to the normal oxidation state, the zero oxidation state is also shown by these elements in complexes.
2. In the highest oxidation states, the transition metal shows basic character and forms cationic complexes.
3. In the highest oxidation states of the first five transition elements (Sc to Mn), all the 4s and 3d electrons are used for bonding.
4. Once the d5 configuration is exceeded, the tendency to involve all the 3d electrons in bonding decreases.

Subtopic:  d-Block Elements- Properties & Uses |
 70%
From NCERT
JEE
Please attempt this question first.
Hints
Please attempt this question first.

If dichromate ion is treated with base, the oxidation number of Cr in the product formed will be:

1. +6

2. +4

3. +5

4. +2

Subtopic:  Chemistry of Mn and Cr Compounds |
 75%
From NCERT
JEE
Please attempt this question first.
Hints
Please attempt this question first.

Lanthanoids does not form MO2 among the following is-[M is lanthanoid metal]

1. Pr

2. Dy

3. Nd

4. Yb

Subtopic:  Lanthanoid & Actinoids Contraction |
 71%
From NCERT
JEE
Please attempt this question first.
Hints
Please attempt this question first.

advertisementadvertisement

On treating a compound with warm dil. H2SO4, gas X is evolved which turns K2Cr2O7 paper acidified with dil. H2SO4 to a green compound Y. X and Y respectively are -

1. X=SO2,Y=Cr2O3

2. X=SO3,Y=Cr2O3

3. X=SO2,Y=Cr2(SO4)3

4. X=SO3,Y=Cr2(SO4)3

Subtopic:  Chemistry of Mn and Cr Compounds |
JEE
Please attempt this question first.
Hints

Given below are two statements:

Statement I: CeO2 can be used for the oxidation of aldehydes and ketones.

Statement II: Aqueous solution of EuSO4 is a strong reducing agent.

In the light of the above statements, choose the correct answer from the options given below:

1. Statement I is false but statement II is true

2. Statement I is true but statement II is false

3. Both statement I and statement II are true

4. Both statement I and statement II are false

Subtopic:  d-Block Elements- Properties & Uses |
 67%
JEE
Please attempt this question first.
Hints

The lanthanoid that does not show +4 oxidation state is:

1. Dysprosium (Dy) 2. Europium (Eu)
3. Cerium (Ce) 4. Terbium (Tb)
Subtopic:  Lanthanoid & Actinoids Contraction |
 68%
From NCERT
JEE
Please attempt this question first.
Hints
Please attempt this question first.

advertisementadvertisement

The incorrect statement among the following is: 

1. VOSO3 is a reducing agent.

2. Cr2O4 is an amphoteric oxide.

3. RuO4 is an oxidizing agent.

4. Red color of ruby is due to the presence of Co3+.

Subtopic:  d-Block Elements- Properties & Uses |
JEE
Please attempt this question first.
Hints