The set of oxides of nitrogen that are paramagnetic in nature is:

1. NO, N₂O

2. N₂O₃, NO

3. NO, NO₂

4. N₂O, NO₂

Which of the following factors are favourable for the formation of an ionic bond?

The correct Lewis structure of acetic acid is:

1.		2.
3.		4.	None of the above.

What is the correct sequence of bond order for the specified species?

The electronic configurations of the elements A, B, and C are given below.

$\mathrm{A}<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>=<mspace\; width="1em"></mspace>1{\mathrm{s}}^2<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>2{\mathrm{s}}^2<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>2{\mathrm{p}}^6$
$\mathrm{B}<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>=<mspace\; width="1em"></mspace>1{\mathrm{s}}^2<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>2{\mathrm{s}}^2<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>2{\mathrm{p}}^6<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>3{\mathrm{s}}^2<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>3{\mathrm{p}}^3$
$\mathrm{C}<mspace\; width="1em"></mspace>=<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>1{\mathrm{s}}^2<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>2{\mathrm{s}}^2<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>2{\mathrm{p}}^6<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>3{\mathrm{s}}^2<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>3{\mathrm{p}}^5$

The bond between B and C will be : 

The electronic configurations of the elements A, B, and C are given below.

$\mathrm{A}<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>=<mspace\; width="1em"></mspace>1{\mathrm{s}}^2<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>2{\mathrm{s}}^2<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>2{\mathrm{p}}^6$
$\mathrm{B}<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>=<mspace\; width="1em"></mspace>1{\mathrm{s}}^2<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>2{\mathrm{s}}^2<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>2{\mathrm{p}}^6<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>3{\mathrm{s}}^2<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>3{\mathrm{p}}^3$
$\mathrm{C}<mspace\; width="1em"></mspace>=<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>1{\mathrm{s}}^2<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>2{\mathrm{s}}^2<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>2{\mathrm{p}}^6<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>3{\mathrm{s}}^2<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>3{\mathrm{p}}^5$

The stable form of A may be represented by the formula:

The correct order of the boiling points of \(\mathrm{H}_2 \mathrm{O}, \mathrm{HF}, \text{ and} \ \mathrm{NH}_3\) is: 

1. HF > H₂O > NH₃

2. H₂O > HF > NH₃

3. NH₃ > HF > H₂O

4. NH₃ > H₂O > HF

The decreasing order of ionic character of the N-H, F-H, C-H, and O-H, is :  

The correct relationship for the bond angle of water and dimethyl ether $\left({\mathrm{CH}}_3-\underset{..}{\overset{..}{\mathrm{O}}}-{\mathrm{CH}}_3\right)$ is: 

Match the compounds of Xe in column I with the molecular structure in column II.