Given below are two statements:
Assertion (A): | Sodium chloride, formed by the action of chlorine gas on sodium metal, is a stable compound. |
Reason (R): | Sodium and chloride ions acquire octets in sodium chloride formation. |
1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
3. | (A) is True but (R) is False. |
4. | (A) is False but (R) is True. |
Given below are two statements:
Assertion (A): | Though the central atom of both NH3 and H2O molecules are sp3 hybridised, yet H-N-H bond angle is greater than that of H-O-H. |
Reason (R): | This is because nitrogen atom has one lone pair and oxygen atom has two lone pairs. |
1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
3. | (A) is true but (R) is false. |
4. | (A) is false but (R) is true. |
Given below are two statements:
Assertion (A): | Among the two O-H bonds in H2O molecule, the energy required to break the first O-H bond and the other O-H bond is the same. |
Reason (R): | The electronic environment around oxygen is the same even after the breakage of one O-H bond. |
1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
3. | (A) is True but (R) is False. |
4. | Both (A) and (R) are False. |
Match the shape of molecules in Column I with the type of hybridization in Column II.
Column I |
Column II |
A. Tetrahedral |
1. sp2 |
B. Trigonal |
2. sp |
C. Linear |
3. sp3 |
Codes
Options: | A | B | C |
1. | 3 | 1 | 2 |
2. | 1 | 2 | 3 |
3. | 5 | 4 | 3 |
4. | 4 | 5 | 3 |
Match the items given in Column I with examples given in Column II.
Column I |
Column II |
A. Hydrogen bond |
1. C |
B. Resonance |
2. LiF |
C. Ionic solid |
3. H2 |
D. Covalent solid |
4. HF |
5. O3 |
Codes
Options: | A | B | C | D |
1. | 2 | 3 | 4 | 1 |
2. | 1 | 2 | 3 | 5 |
3. | 5 | 4 | 3 | 2 |
4. | 4 | 5 | 2 | 1 |
Match the species in Column I with the bond order in Column II.
Column I |
Column II |
A. NO |
1. 1.5 |
B. CO |
2. 2.0 |
C. O2- |
3. 2.5 |
D. O2 |
4. 3.0 |
Codes
Options: | A | B | C | D |
1. | 3 | 4 | 1 | 2 |
2. | 1 | 2 | 3 | 5 |
3. | 5 | 4 | 3 | 2 |
4. | 4 | 5 | 3 | 2 |
Match the species in Column I with the shape in Column II.
Column I |
Column II |
A. H3O+ |
1. Linear |
B. HCCH |
2. Angular |
C. ClO2- |
3. Tetrahedral |
D. NH4+ |
4. Trigonal bipyramidal |
5. Pyramidal |
Codes
Options: | A | B | C | D |
1. | 5 | 1 | 2 | 3 |
2. | 1 | 2 | 3 | 5 |
3. | 5 | 4 | 3 | 2 |
4. | 4 | 5 | 3 | 2 |
Match the species in Column I with the type of hybrid orbitals in Column II.
Column I |
Column II |
A. SF4 |
1. sp3d2 |
B. IF5 |
2. d2sp3 |
C. NO2+ |
3. sp3d |
D. NH4+ |
4. sp3 |
5. sp |
Codes
Options: | A | B | C | D |
1. | 3 | 1 | 5 | 4 |
2. | 1 | 2 | 3 | 5 |
3. | 5 | 4 | 3 | 2 |
4. | 4 | 5 | 3 | 2 |
Match the compounds of Xe in Column I with the molecular structure in Column II.
Column-I | Column-II | ||
(a) | XeF2 | (i) | Square planar |
(b) | XeF4 | (ii) | Linear |
(c) | XeO3 | (iii) | Square pyramidal |
(d) | XeOF4 | (iv) | Pyramidal |
(a) | (b) | (c) | (d) | |
1. | (ii) | (i) | (iii) | (iv) |
2. | (ii) | (iv) | (iii) | (i) |
3. | (ii) | (iii) | (i) | (iv) |
4. | (ii) | (i) | (iv) | (iii) |
Match the coordination number and type of hybridization with the distribution of hybrid orbitals in space based on Valence bond theory.
Coordination number and type of hybridisation | Distribution of hybrid orbitals in space | ||
(a) | 4, sp3 | (i) | Trigonal bipyramidal |
(b) | 4, dsp2 | (ii) | Octahedral |
(c) | 5, sp3d | (iii) | Tetrahedral |
(d) | 6, d2sp3 | (iv) | Square planar |
(a) | (b) | (c) | (d) | |
1. | (ii) | (iii) | (iv) | (i) |
2. | (iii) | (iv) | (i) | (ii) |
3. | (iv) | (i) | (ii) | (iii) |
4. | (iii) | (i) | (iv) | (ii) |