If 4 g of NaOH dissolves in 36 g of H2O, the molarity of the solution is: (specific gravity of solution is 1 g mL-1) : 

1. 3 M 2. 3.5 M
3. 2.5 M 4. 2 M

Subtopic:  Concentration Based Problem |
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On complete decomposition, the volume of CO2 released at STP on heating 9.85 g of BaCO3 (atomic mass, Ba = 137) will be:

1. 1.12 L

2. 4.84 L

3. 2.12 L

4. 2.06 L

Subtopic:  Limiting Reagent |
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The amount of Zinc (atomic weight=65) necessary to produce 224 mL of H2 (at STP) by the reaction with dilute sulphuric acid will be: 

1. 0.65 g 2. 7.6 g
3. 6.5 g 4. 8.5 g
Subtopic:  Limiting Reagent |
 81%
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The number of valence electrons present in 0.53 grams of Na2COis:

1. 3.01×1023

2. 7.22×1022

3. 12.046×1023

4. 6.023×1023

Subtopic:  Moles, Atoms & Electrons |
 60%
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The number of  moles  present in 2.5 litres of 0.2 M  H2SO4 are:

1. 0.25

2. 0.5

3. 0.75

4. 0.2

Subtopic:  Moles, Atoms & Electrons |
 85%
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 The maximum number of molecules is present in which of the following? 

1. 15 L of H2 gas at STP

2. 5 L of N2 gas at STP

3. 0.5 g of H2 gas

4. 10 g of O2 gas

Subtopic:  Moles, Atoms & Electrons |
 71%
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Two students performed the same experiment separately, and each of them recorded two readings of mass, which are given below. The correct reading of mass is 3.0 g. On the basis of the given data, mark the correct option out of the following statements.

Students Readings
(i) (ii)
    A 3.01 2.99
    B 3.05 2.95

1. The results of both the students' are neither accurate nor precise.
2. The results of student A are both precise and accurate.
3. Student B's results are neither precise nor accurate.
4. The results of student B are both precise and accurate.

Subtopic:  Introduction |
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If 500 mL of a 5 M solution is diluted to 1500 mL, the molarity of the resultant solution is: 

1. 1.5 M

2. 1.66 M

3. 0.017 M

4. 1.59 M

Subtopic:  Concentration Based Problem |
 82%
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Mark the species among the following that contains the highest number of atoms.

1. 4 g He

2. 46 g Na

3. 0.40 g Ca

4. 12 g He

Subtopic:  Moles, Atoms & Electrons |
 84%
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The empirical formula and molecular mass of a compound are CH2O and 180 g, respectively. The molecular formula of the compound is -

1.  C9H18O9 2.  CH2O
3.  C6H12O6 4.  C2H4O2
Subtopic:  Empirical & Molecular Formula |
 89%
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