- 1(current)
Q. No.If the radius of \(_{13}^{27}\mathrm{Al}\) nucleus is taken to be \({R}_{\mathrm{Al}},\) then the radius of \(_{53}^{125}\mathrm{Te}\) nucleus is near:
| 1. | \(\left(\frac{53}{13}\right) ^{\frac{1}{3}}~{R_{Al}}\) | 2. | \(\frac{5}{3}~{R_{Al}}\) |
| 3. | \(\frac{3}{5}~{R_{Al}}\) | 4. | \(\left(\frac{13}{53}\right)~{R_{Al}}\) |
Subtopic: Â Nucleus |
 81%
Level 1: 80%+
NEET - 2015
Hints
Links
If the nuclear radius of \(^{27}\text{Al}\) is \(3.6\) Fermi, the approximate nuclear radius of \(^{64}\text{Cu}\) in Fermi is:
1. \(2.4\)
2. \(1.2\)
3. \(4.8\)
4. \(3.6\)
Subtopic: Â Nucleus |
 89%
Level 1: 80%+
AIPMT - 2012
Hints
Links
Two nuclei have their mass numbers in the ratio of \(1:3.\) The ratio of their nuclear densities would be:
1. \(1:3\)
2. \(3:1\)
3. \((3)^{1/3}:1\)
4. \(1:1\)
Subtopic: Â Nucleus |
 82%
Level 1: 80%+
AIPMT - 2008
Hints
Links
If the nucleus \({}_{13}^{27}\mathrm{Al}\) has a nuclear radius of about \(3.6\) fermis, then \({}_{52}^{125}\mathrm{Te}\) would have its radius approximately as:
1. \(6.0\) Fermi
2. \(9.6\) Fermi
3. \(12.0\) Fermi
4. \(4.8\) Fermi
1. \(6.0\) Fermi
2. \(9.6\) Fermi
3. \(12.0\) Fermi
4. \(4.8\) Fermi
Subtopic: Â Nucleus |
 73%
Level 2: 60%+
AIPMT - 2007
Hints
Links
The radius of Germanium \((\mathrm{Ge})\) nuclide is measured to be twice the radius of \({}_{4}^{9}\mathrm{Be}.\) The number of nucleons in \(\mathrm{Ge}\) is:
1. \(73\)
2. \(74\)
3. \(75\)
4. \(72\)
Subtopic: Â Nucleus |
 65%
Level 2: 60%+
AIPMT - 2006
Hints
Links
- 1(current)
Q. No.
© 2026 GoodEd Technologies Pvt. Ltd.