Arrange the following amines in decreasing order of basicity:
(A)   (B) 
(C)  (D) 
1. (A) > (C) > (D) > (B) 
2. (C) > (A) > (B) > (D) 
3. (B) > (C) > (D) > (A) 
4. (C) > (B) > (A) > (D) 
Subtopic:  Amines - Preparation & Properties |
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Consider the given two statements:
Statement I: In the Hofmann rearrangement reaction, the alkyl group shifts from a carbonyl carbon atom to the nitrogen atom. 
Statement II: The tertiary amine formed in Hofman rearrangement reaction contains one carbon less than that present in the original amide.
 
1. Both Statement I & Statement II are true.
2. Both Statement I & Statement II are false.
3. Statement I is true while Statement II is false.
4. Statement I is false while Statement II is true.
Subtopic:  Amines - Preparation & Properties |
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Assertion (A): In strongly acidic solutions, aniline becomes more reactive towards electrophilic reagents.
Reason (R): The amino group being completely protonated in a strongly acidic solution, the lone pair of electrons on the nitrogen is no longer available for resonance
 
1. Both (A) & (R) are True and the reason is the correct explanation of the (A).
2. Both (A) & (R) are True but the reason is not the correct explanation of the (A).
3. (A) is True but (R) is False.
4. (A) is False but (R) is True.
Subtopic:  Amines - Preparation & Properties |
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Match the organic compounds given in List–I with their corresponding pKb given in List–II:
Amine (List–I) List - II pKb (aqueous medium)
A. Aniline (i) 9.0
B. Ethanamine (ii) 3.29
C. N-Ethylethanamine (iii) 3.25
D. N,N-diethylethanamine (iv) 3.0
 
A B C D
1. (i) (ii) (iv) (iii)
2. (i) (iv) (iii) (ii)
3. (i) (ii) (iii) (iv)
4. (ii) (iii) (iv) (i)
Subtopic:  Amines - Preparation & Properties |
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The most reactive amine towards dilute hydrochloric acid is:

1. 2.
3. 4.
Subtopic:  Amines - Preparation & Properties |
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Which of the following will produce the highest yield in Friedel Crafts reaction? 
1.  2. 
3.  4. 
Subtopic:  Amines - Preparation & Properties |
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Consider the given two statements:
Assertion (A): p-Toluidine is a stronger base than m-toluidine.
Reason (R): The methyl group from m-position exerts a smaller electron-donating inductive (+l) effect than from p-position.
Options:
1. Both (A) and (R) are True and (R) is the correct explanation for (A).
2. Both (A) and (R) are True but (R) is not the correct explanation for (A).
3. (A) is True but (R) is False.
4. Both (A) and (R) are False.
Subtopic:  Amines - Preparation & Properties |
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Which of the following should be most volatile?

I.  \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{NH}_2\)
II.  \(\left(\mathrm{CH}_3\right)_3 \mathrm{~N}\)
III. 
IV.  \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_3\)

 

1. II 2. IV
3. I 4. III
Subtopic:  Amines - Preparation & Properties |
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In the following reaction sequence,  
 
the major products X and Z are:
 
1.
2.
3.
4.
Subtopic:  Amines - Preparation & Properties | Mechanism |
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\(R-COOH\xrightarrow[(2)~Br_2/KOH]{(1)~ND_3,~\Delta}A~\text(major).\)
The compound \('A'\) is:
1. \(R-COND_2\)
2. \(R-NH_2\)
3. \(R-ND_2\)
4. \(R-CONH_2\)
Subtopic:  Amines - Preparation & Properties |
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