Copper forms two oxides. For the same amount of copper, twice as much oxygen was used to form the first oxide as to form the second one. What is the ratio of the valencies of copper in the first and second oxides?
 

1. 2:5

2. 1:6

3. 2:1

4. 1:2

 64%
Level 2: 60%+
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5 mL of a gaseous hydrocarbon was exposed to 30 mL of O2. The resultant gas, on cooling is found to measure 25 mL of which 10 mL is absorbed by NaOH and the remainder by pyrogallol. Determine molecular formula of hydrocarbon. All measurements are made at constant room temperature.

1. CH4

2. C2H2

3. C3H4

4. C2H4

Subtopic:  Limiting Reagent |
Level 3: 35%-60%
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2.0 g sample containing Na2CO3and NaHCO3 loses 0.248 g when heated to 300°C, the temperature at which NaHCO3 decomposes to Na2CO3CO2 and H2O. What is the % of Na2CO3 in mixture?

1.66.5

2.50.6

3.60.5

4.6.65

Subtopic:  Equation Based Problem |
 53%
Level 3: 35%-60%
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A sample of CaCO3 and MgCO3 weighed 2.21 g is ignited to constant mass of 1.152 g. Calculate the volume of CO2 evolved at 0°C and 76 cm of pressure.

1.640 ml

2.540 ml

3.500 ml

4.600 ml

Subtopic:  Moles, Atoms & Electrons |
 68%
Level 2: 60%+
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The average molar mass of the mixture of CH4 and C2H4 present in the mole ratio of a:b is
20 g mol-1. When the mole ratio is reversed, the molar mass of the mixture will be:

1. 24 gram 2. 42 gram
3. 20 gram 4. 15 gram
Subtopic:  Moles, Atoms & Electrons |
Level 3: 35%-60%
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Vapour density of a volatile substance is 4 CH4=1. Its molar mass would be:

1.  8

2.  2

3.  64

4.  128

Subtopic:  Moles, Atoms & Electrons |
Level 3: 35%-60%
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The vapour density of a volatile chloride of a metal is 95 and the specific heat of the metal is 0.13 cal/g. The equivalent mass of the metal will be:

1.  6 g
2. 12 g
3.  18 g
4.  24 g

Subtopic:  Moles, Atoms & Electrons |
 65%
Level 2: 60%+
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O3 is absorbed by:

1.  Pyrogallol

2.  Menthol

3.  Turpentine oil

4.  Clove oil

Subtopic:  Introduction |
 60%
Level 2: 60%+
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The mass of one molecule of compound C60H122 is:
1. \(1.3 \times 10^{-20} \mathrm{~g} \)
2. \(5.01 \times 10^{-21} \mathrm{~g} \)
3. \(3.72 \times 10^{-23} \mathrm{~g}\)
4. \(1.4 \times 10^{-21} \mathrm{~g}\)

Subtopic:  Moles, Atoms & Electrons |
 56%
Level 3: 35%-60%
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Read the following statements (S) and Explanation (E). Choose the correct answers from the codes (1), (2), (3) and (4):

S : An element may have variable equivalent mass.

E : Such elements should possess variable valency. 

1.  S is correct but E is wrong
2.  S is wrong but E is correct
3.  Both S and E are correct and E is correct explanation of S
4.  Both S and E are correct but E is not correct explanation of S

Subtopic:  Millimole/Equivalent Concept |
 70%
Level 2: 60%+
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