In producing chlorine through electrolysis, 100 W power at 125 V is being consumed.
The liberation of chlorine per min is:

(ECE of chlorine is 0.367×10^-6 kg/C)

1.	17.6 mg	2.	21.3 mg
3.	24.3 mg	4.	13.6 mg

The reduction potential of the two half cell
reactions (occuring in an electrochemical cell)
are
PbSO₄(s) + 2e^– $\to$ Pb(s) + ${\mathrm{SO}}_4^{2-}$(aq) (E°= –0.31V)
Ag⁺(aq) + e^– $\to$ Ag(s) (E° = 0.80V)

The feasible reaction will be
1. Pb(s) + ${\mathrm{SO}}_4^{2-}$(aq) + 2 Ag⁺(aq)$\to$  2Ag (s) + PbSO₄ (s)
2. PbSO₄(s) + Ag⁺ (aq) $\to$ Pb(s)+${\mathrm{SO}}_4^{2-}$(aq) + 2Ag(s)
3. Pb(s) + ${\mathrm{SO}}_4^{2-}$ (s) + Ag(s) $\to$Ag⁺(aq) + PbSO₄(s)
4. PbSO₄(s) +Ag(s) $\to$ Ag⁺(aq) + Pb(s) +${\mathrm{SO}}_4^{2-}$ (aq)

The cell potential will be:

An excess of liquid Hg was added to 10^–3 M acidified solution of ${\mathrm{Fe}}^{3+}$ ions. It was found that only 5% of the ions remained as Fe⁺³ at equilibrium at 25ºC. What is Eº for 2Hg/Hg₂⁺² at 25ºC for-                     

   2Hg + 2Fe⁺³   $\rightleftharpoons$   ${\mathrm{Hg}}_2^{2+}$ + $2{\mathrm{Fe}}^{+2}$

and   ${\mathrm{E}}_{{\mathrm{Fe}}^{+2}/{\mathrm{Fe}}^{+3}}^0$   = 0.77 V

1. – 1.347 V               

2. – 0.793 V

3. – 0.125 V               

4. – 1.110V

How many second would it take to produce enough aluminum by the Hall process to make a case of 24 cans of aluminum soft-drink, if each can uses 5.0 g of Al, a current of 9650 amp is employed, and the current efficiency of the cell is 90.0%:

(1) 203.2

(2) 148.14

(3) 333

(4) 6.17

The electrolysis of acetate solution produces ethane according to reaction:

$2C{H}_{3}CO{O}^{-}\to C_2{H}_6\left(g\right)+2C{O}_2\left(g\right)+2e^{-}$

The current efficiency of the process is 80%.  What volume of gases would be produced at 27$°$C and 740 torr, if the current of 0.5 amp is passed through the solution for 96.45 min?

(1) 6.0 L                   (2) 0.60 L                   (3) 1.365 L                       (4) 0.91 L

A fuel cell develops an electrical potential from the coombustion of butane at 1 bar and 298 K

$C_4{H}_{10}\left(g\right)+6.5O_2\left(g\right)\to 4C{O}_2\left(g\right)+5H_{2}O\left(l\right);$
${∆}_r{G}^{°}=-2746 kJ/mol$

What is $E^{°}$ of a cell?

(1) 4.74 V

(2) 0.547 V

(3) 4.37 V

(4) 1.09 V

Given the following molar conductivities at ${25}^{°}C:, HCl 426 {\Omega }^{-1} c{m}^2 mo{l}^{-1};$
$$$NaCl 126 {\Omega }^{-1} c{m}^2 mo{l}^{-1}; NaC (sodium coronate)$$83 {\Omega }^{-1} c{m}^2 mo{l}^{-1}$.  what is the ionization constant of crotonic acid? If the conductivity of a 0.001 M crotonic acid solution is 3.83$\times$${10}^{-5} {\Omega }^{-1}c{m}^{-1}$?

(1) ${10}^{-5}$                 (2) $1.11\times {10}^{-5}$

(3) $1.11\times {10}^{-4}$      (4)0.01

Which of the following solutions has the highest equivalent conductance?

1. 0.01 M NaCl

2. 0.05 M NaCl

3. 0.005 M NaCl

4. 0.02 M NaCl

For a reaction,  A(s) + 2B⁺ $\to$ A²⁺ + 2B(s) ; K_C  has been found to be 10¹². The  ${\mathrm{E}}_{\mathrm{cell}}^{°}$ is
1. 0.354 V

2. 0.708V

3. 0.0098 V

4. 1.36V