Based on electrode potentials in the table below: 
Cu2+(aq) + e- → Cu+(aq) 0.15 V
Cu+(aq) + e- → Cu(s) 0.50 V

The value of \(E_{Cu^{2+}/Cu}^{o}\) will be:
1. 0.325 V 2. 0650 V
3. 0.150 V 4. 0.500 V

Subtopic:  Electrode & Electrode Potential |
 63%
Level 2: 60%+
AIPMT - 2011
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Standard electrode potential for Sn4+/Sn2+ couple is +0.15 V and that for Cr3+/Cr couple is -0.74. These two couples in their standard state are connected to make a cell. The cell potential will be:

1. +0.89 V

2. +0.18 V

3. +1.83 V

4. +1.199 V

Subtopic:  Electrode & Electrode Potential |
 91%
Level 1: 80%+
AIPMT - 2011
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In producing chlorine by electrolysis, 100 kW power at 125 V is being consumed.
How much chlorine per minute is liberated:
(Given -ECE of chlorine is 0.367 X 10-6 kgC-1)

1.1.76×10-3 kg

2. 9.67×10-3 kg

3. 17.61×10-3 kg

4. 3.67×10-3 kg

Subtopic:  Faraday’s Law of Electrolysis |
 55%
Level 3: 35%-60%
AIPMT - 2010
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For the reduction of silver ions with copper metal, the standard cell potential was found to be +0.46 V at 25 °C. The value of standard Gibbs energy, ΔGo will be: 

(F = 96500 C mol-1)

1. -89.0 kJ

2. -89.0 J

3. -44.5 kJ

4. -98.0 kJ

Subtopic:  Faraday’s Law of Electrolysis |
 72%
Level 2: 60%+
AIPMT - 2010
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Al2Ois reduced by electrolysis at low potentials and high currents. If 4.0 x 10A of current is passed through molten Al2O3 for 6 hours, the mass of aluminum produced is:
(Assume 100 % current efficiency, the atomic mass of Al = 27 g mol-1)

1. 9.0 x 103 g 2. 8.1 x 104 g
3. 2.4 x 105 g 4. 1.3 x 104 g
Subtopic:  Faraday’s Law of Electrolysis |
 66%
Level 2: 60%+
AIPMT - 2009
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The molar conductance of M32 solution of a weak monobasic acid is 8.0 ohm-1 cmand at infinite dilution is 400 ohm-1 cm2. The dissociation constant of this acid is: 

1. \(1.25 \times10^{-5}\) 2. \(1.25 \times10^{-6}\)
3. \(6.25 \times10^{-4}\) 4. \(1.25 \times10^{-4}\)
Subtopic:   Kohlrausch Law & Cell Constant |
 66%
Level 2: 60%+
AIPMT - 2009
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Given:
(i) Cu2++2e-Cu    Eo = 0.337 V 
(ii) Cu2++e-Cu+  Eo = 0.153 V 
Electrode potential, Eo for the reaction, 
Cu++e-Cu, will be: 

1. 0.52 V

2. 0.90 V

3. 0.30 V

4. 0.38 V

Subtopic:  Relation between Emf, G, Kc & pH |
 76%
Level 2: 60%+
AIPMT - 2009
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Kohlrausch's law states that at:

1. Finite dilution, each ion makes definite contribution to equivalent conductance of an electrolyte, whatever be the nature of the other ion of the electrolyte.
2. Infinite dilution, each molecule makes definite contribution to equivalent conductance of an electrolyte depending on the nature of the other ion of the electrolyte.
3. Finite dilution, each molecule makes definite contribution to conductance of an electrolyte whatever be the nature of the other ion of the electrolyte.
4. Infinite dilution, each ion makes definite contribution to equivalent conductance of an electrolyte, whatever be the nature of the other ion of the electrolyte.
Subtopic:   Kohlrausch Law & Cell Constant |
 59%
Level 3: 35%-60%
AIPMT - 2008
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A steady current of 1.5 A flows through a copper voltmeter for 10 min. If the electrochemical equivalent of copper is 30 × 10-5 g C-1, the mass of copper deposited on the electrode will be:

1. 0.40 g

2. 0.50 g

3. 0.67 g

4. 0.27 g

Subtopic:  Faraday’s Law of Electrolysis |
 77%
Level 2: 60%+
AIPMT - 2007
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For a given reaction, 
Cu(s) + 2Ag+ (aq) → Cu2+(aq)+2Ag(s); 
E0=0.46 V at 298 K . The equilibrium constant will be :

1. 2.4×1010 2. 2.0×1010
3. 4.0×1010 4. 4.0×1015
Subtopic:  Nernst Equation | Relation between Emf, G, Kc & pH |
 64%
Level 2: 60%+
AIPMT - 2007
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