If the distance 's' travelled by a body in time 't' is given by s=at+bt2 then the acceleration equals

(A)  2at3+2b

(B)  2st3

(C)  2b-2at3

(D)  st2

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The velocity of a particle moving on the x-axis is given by v=x2+x where v is in m/s and x is in m. Find its acceleration in m/s2 when passing through the point x=2m.

1.  0

2.  5

3.  11

4.  30

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A particle moves in the XY plane and at time t is at the point whose coordinates are t2, t3-2t. Then at what instant of time, will its velocity and acceleration vectors be perpendicular to each other?

(A)  1/3 sec

(B)  2/3 sec

(C)  3/2 sec

(D)  never

Concept Questions :-

Differentiation
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A particle moves in the x-y plane with velocity vx=8t-2 and vy=2. If it passes through the point x=14 and y=4 at t=2 sec. The equation of the path is

(A)  x=y2-y+2

(B)  x=y+2

(C)  x=y2+2

(D)  x=y2+y+2

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A motor boat of mass m moving along a lake with velocity V0. At t=0, the engine of the boat is shut down. Magnitude of resistance force offered to the boat is equal to rV. (V is instantaneous speed). What is the total distance covered till it stops completely? Hint: Fx=mVdVdx=-rV

(A)  mV0/r

(B)  3 mV0/2r

(C)  mV0/2r

(D)  2mV0/r

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A particle is moving along positive x-axis. Its position varies as x=t3-3t2+12t+20, where x is in meters and t is in seconds.

Initial velocity of the particle is

(A)  1 m/s

(B)  3 m/s

(C)  12 m/s

(D)  20 m/s

Concept Questions :-

Differentiation
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A particle is moving along positive x-axis. Its position varies as x=t3-3t2+12t+20, where x is in meters and t is in seconds.

Initial acceleration of the particle is

(A)  Zero

(B)  1 m/s2

(C)  -3 m/s2

(D)  -6 m/s2

Concept Questions :-

Differentiation
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A particle is moving along positive x-axis. Its position varies as x=t3-3t2+12t+20, where x is in meters and t is in seconds.

Velocity of the particle when its acceleration zero is

(A)  1 m/s

(B)  3 m/s

(C)  6 m/s

(D)  9 m/s

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Differentiation
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Two forces F1=2i^+2j^ N and F2=3j^+4k^ N are acting on a particle.

The resultant force acting on particle is:

(A)  2i^+5j^+4k^

(B)  2i^-5j^-4k^

(C)  i^-3j^-2k^

(D)  i^-j^-k^

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Two forces F1=2i^+2j^ N and F2=3j^+4k^ N are acting on a particle.

The angle between F1 & F2 is:

(A)  θ=cos-1325

(B)  θ=cos-1352

(C)  θ=cos-1235

(D)  θ=cos-135

Concept Questions :-

Resultant of Vectors
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