A=i^+j^-k^ ; B=2i^+3j^+5k^ angle between A and B is

(A)  120°

(B)  90°

(C)  60°

(D)  30°

Concept Questions :-

Scalar Product
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Given the vectors

                         A=2i^+3j^-k^                         B=3i^-2j^-2k^&                      C=pi^+pj^+2pk^

Find the angle between A-B & C

(A)  θ=cos-123

(B)  θ=cos-132

(C)  θ=cos-123

(D)  none of these

Concept Questions :-

Scalar Product
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If vector P, Q and R have magnitude 5, 12 and 13 units and P+Q=R the angle between Q and R is -

(A)  cos-1 512

(B)  cos-1 513

(C)  cos-1 1213

(D)  cos-1 213

Concept Questions :-

Resultant of Vectors
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The vector having a magnitude of 10 and perpendicular to the vector 3i^-4j^ is 

1. 4i^+3j^

2. 52 i^-52 j^

3. 8i^+6j^

4.  8i^-6j^

Concept Questions :-

Scalar Product
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A force F=3i^+cj^+2k^ acting on a particle causes a displacement d=-4i^+2j^+3k^. If the work done is 6J then the value of 'c' is

(A)  12 

(B)  0

(C)  6

(D)  1

Concept Questions :-

Scalar Product
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A particle moving along a straight line according to the law x=At+Bt2+Ct3, where x is its position measured from a fixed point on the line and t is the time elapsed till it reaches position x after starting from the fixed point. Here A, B and C are positive constants.

(A)  Its velocity at t=0 is A

(B)  Its acceleration at t=0 is B

(C)  Its velocity at t=0 is B

(D)  Its acceleration at t=0 is C

Concept Questions :-

Differentiation
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If the velocity of a particle moving on x-axis is given by v=3t2-12t+6. At which time is the acceleration of particle zero?

(A)  2 sec

(B)  2+2 sec

(C)  2-2 sec

(D)  zero

Concept Questions :-

Differentiation
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Momentum of a body moving in a straight line is p=t2+2t+1 kg m/s. Find the force acting on a body at t=2 sec

(A)  6 N

(B)  8 N

(C)  4 N

(D)  2 N

Concept Questions :-

Differentiation
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A particle moves along straight line such that at time t its position from a fixed point O on the line is x=3t2-2. The velocity of the particle when t=2 is:

(A)  8 ms-1

(B)  4 ms-1

(C)  12 ms-1

(D)  0

Concept Questions :-

Differentiation
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Coordinates of a moving particle are given by x=ct2 and y=bt2. The speed of the particle is given by

(A)  2t c+b

(B)  2t c2-b2

(C)  t c2+b2

(D)  2t c2+b2

Concept Questions :-

Differentiation
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