A vector perpendicular to 4i^-3j^ is -

(A)  4i^+3j^

(B)  7k^

(C)  6i^

(D)  3i^-4j^

Concept Questions :-

Scalar Product
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Angle that the vector A=2i^+3j^ makes with y-axis is -

(A)  tan-1 3/2

(B)  tan-1 2/3

(C)  sin-1 2/3

(D)  cos-1 3/2

Concept Questions :-

Scalar Product
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A vector A points, vertically upward and, B points towards north. The vector product A×B is -

1.  along west

2.  along east

3.  zero

4.  vertically downward

Concept Questions :-

Vector Product
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The linear velocity of a rotating body is given by v=ω×r, where ω is the angular velocity and r is the radius vector. The angular velocity of a body ω=i^-2j^+2k^ and their radius vector r=4j^-3k^, |v| is -

(A)  29 units

(B)  31 units

(C)  37 units

(D)  41 units

Concept Questions :-

Vector Product
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The displacement x of a particle along a straight line at time t is given by x=a0+a1t+a2t2. The acceleration of the particle is

(A)  a0

(B)  a1

(C)  2a2

(D)  a2

Concept Questions :-

Differentiation
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The displacement of a particle is given by y=a+bt+ct2-dt4. The initial velocity and acceleration are respectively

(A)  b, -4d

(B)  -d, 2c

(C)  b, 2c

(D)  2c, -4d

Concept Questions :-

Differentiation
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The momentum is given by p=4t+1, the force at t=2s is

(A)  4 N

(B)  8 N

(C)  10 N

(D)  15 N

Concept Questions :-

Differentiation
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A particle moves along a straight line such that its displacement at any time t is given by s = t3 - 3t2 + 6t - 12 metres. The velocity when the acceleration is zero is:

(A)  3 ms-1

(B)  -12 ms-1

(C)  42 ms-1

(D)  -9 ms-1

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The position x of particle varies with time t as x=at2-bt3. The acceleration of the particle will be zero at time equal to

(A)  ab

(B)  2ab

(C)  a3b

(D)  Zero

Concept Questions :-

Differentiation
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A body is moving according to the equation x=at+bt2-ct3 where x = displacement and a, b and c are constants. The acceleration of the body is

(A)  a+2bt

(B)  2b+6ct

(C)  2b-6ct

(D)  3b-6ct2

Concept Questions :-

Differentiation
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