Q. No.The efficiency of an ideal heat engine (Carnot heat engine) working between the freezing point and boiling point of water is:
1.
\(26.8\%\)
2.
\(20\%\)
3.
\(6.25\%\)
4.
\(12.5\%\)
| Assertion (A): | Thermodynamic process in nature are irreversible. |
| Reason (R): | Dissipative effects cannot be eliminated. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | (A) is False but (R) is True. |
(Take, 1 cal= 4.2 Joules)
1. 23.65 W
2. 236.5 W
3. 2365 W
4. 2.365 W
An ideal gas is compressed to half its initial volume using several processes. Which of the processes results in the maximum work done on the gas?
1. adiabatic
2. isobaric
3. isochoric
4. isothermal
A Carnot engine, having an efficiency of = as a heat engine, is used as a refrigerator. If the work done on the system is \(10\) J, the amount of energy absorbed from the reservoir at a lower temperature is:
1. \(100\) J
2. \(99\) J
3. \(90\) J
4. \(1\) J
| 1. | \(64P\) | 2. | \(32P\) |
| 3. | \(\frac{P}{64}\) | 4. | \(16P\) |
A thermodynamic system undergoes a cyclic process \(ABCDA\) as shown in Fig. The work done by the system in the cycle is:
| 1. | \( P_0 V_0 \) | 2. | \( 2 P_0 V_0 \) |
| 3. | \(\dfrac{P_0 V_0}{2} \) | 4. | zero |
| 1. | \(1000~\text{J}\) | 2. | zero |
| 3. | \(-2000~\text{J}\) | 4. | \(2000~\text{J}\) |
| 1. | \(\dfrac{R}{\gamma -1}\) | 2. | \(\dfrac{\gamma -1}{R}\) |
| 3. | \(\gamma R \) | 4. | \(\dfrac{\left ( \gamma -1 \right )R}{\left ( \gamma +1 \right )}\) |
A thermodynamic system is taken through the cycle \(ABCD\) as shown in the figure. Heat rejected by the gas during the cycle is:
1. \(2 {PV}\)
2. \(4{PV}\)
3. \(\frac{1}{2}{PV}\)
4. \(PV\)
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