NEET Physics Kinetic Theory of Gases Questions Solved


The kinetic energy of one gram molecules of a gas at normal temperature and pressure R=8.31 J/mole-K

1.  0.56×104 J                           

2.  1.3×102 J

3.  2.7×102 J                             

4.  3.4×103 J

4. Kinetic energy per gm mole E=f2RT

    If nothing is said about gas then we should calculate the translation kinetic energy

    i.e.,

       ETrans=32RT=32×8.31×273+0=3.4×103 J

Difficulty Level:

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