Among the following, the strongest base is:

1. C₆H₅NH₂

2. p-NO₂-C₆H₄NH₂

3. m-NO₂-C₂H₄NH₂

4. C₂H5CH₂NH₂

A nitrogenous substance X is treated with HNO₂ and the product so formed is further treated with NaOH solution, which produces blue colouration. X can be:

1. ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{NH}}_2$

2. ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{NO}}_2$

3. ${\left({\mathrm{CH}}_3\right)}_2\mathrm{C}(\mathrm{N}=\mathrm{O})\left({\mathrm{NO}}_2\right)$

4. ${(\mathrm{CH}}_{}$₃)2CHNO2

Alkanamide that gives 1-phenylethylamine on Hoffmann's reaction is:

1. 2-Phenylpropanamide

2. 3-Phenylpropanamide

3. 2-Phenylethanamide

4. N-Phenylethanamide

The IUPAC name of the given comound is -

1. 1-Methyl-aminopropane

2. Butan-2-amine

3. 2-Methyl-2-aminopropane

4. None of the above

The correct order of increasing reactivity of C-X bond towards nucleophile in the following compound is

[2010]

1. I<II<IV<III

2. II<III<I<IV

3. IV<III<I<II

4. III<II<I<IV

Aniline is reacted with bromine water and the resulting product is treated with an aqueous solution of sodium nitrite in presence of dilute hydrochloric acid. The compound so formed is converted into a tertafluoroborate which is subsequently heated. The final product is    

1. 1,3,5-tribromobenzene

2. p-bromofluorobenzene

3. p-bromoaniline

4. 2,4,6-tribromofluorobenzene

Alkyl halide (RX) on treatment with KCN followed by reduction leads to the formation of:

1. RNH₂

2. RCH₂NH₂

3. RH + NH₃

4. RCH₃ + N₂

The end product in the following sequence of reactions is -

${\mathrm{C}}_2{\mathrm{H}}_5{\mathrm{NH}}_2\stackrel{{\mathrm{HNO}}_2}{\to }A \stackrel{{\mathrm{PCl}}_5}{\to }B\stackrel{{\mathrm{NH}}_3}{\to }C?$
$$

1. Ethyl cyanide

2. Ethylamine

3. Methylamine

4. Acetamide

The product[A] formed in the reaction; $2{\mathrm{C}}_5{\mathrm{H}}_5-\mathrm{CN}\underset{{\mathrm{Et}}_2\mathrm{O}}{\overset{\mathrm{Na}}{\to }} \left[\mathrm{A}\right] \mathrm{is}:\mathrm{C}$

1. 

2. 

3. 

4. 

CH₃CH₂NH₂ contains a basic NH₂ group, but CH₃CONH₂ does not, because;

1. acetamide is amphoteric in character

2. in CH₃CH₂NH₂ the electron pair on N-atom is delocalized by resonance

3. in CH₃CH₂NH₂ there is no resonance, while in acetamide the lone pair of electron on N-atom is delocalized and therefore less available for protonation

4. none of the above