When NaNO₂ and dilute HCl were added to an amine at $0°\mathrm{c}$, a colourless gas was evolved and an ionic compound is formed. The amine is:

1. any primary amine

2. an aromatic primary amine

3. any amine

4. none of the above

The compound obtained by heating a mixture of primary amine and chloroform with ethanolic potassium hydroxide (KOH) is

[1997]

1. An alkyl isocyanide

2. An alkyl halide

3. An amide

4. An amide and nitro compound

Identify 'Z' in the change;

${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NH}}_2\underset{280\mathrm{K}}{\overset{{\mathrm{NaNO}}_2/\mathrm{HCl}}{\to }}\mathrm{X}\stackrel{\mathrm{CuBr}/\mathrm{HBr}}{\to }\mathrm{Z}:$




 

1.
2.
3.
4.

1.  

2. 

3. 

4.  

Among the following, the strongest base is:

1. C₆H₅NH₂

2. p-NO₂-C₆H₄NH₂

3. m-NO₂-C₂H₄NH₂

4. C₂H5CH₂NH₂

A nitrogenous substance X is treated with HNO₂ and the product so formed is further treated with NaOH solution, which produces blue colouration. X can be:

1. ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{NH}}_2$

2. ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{NO}}_2$

3. ${\left({\mathrm{CH}}_3\right)}_2\mathrm{C}(\mathrm{N}=\mathrm{O})\left({\mathrm{NO}}_2\right)$

4. ${(\mathrm{CH}}_{}$₃)2CHNO2

Alkanamide that gives 1-phenylethylamine on Hoffmann's reaction is:

1. 2-Phenylpropanamide

2. 3-Phenylpropanamide

3. 2-Phenylethanamide

4. N-Phenylethanamide

The IUPAC name of the given comound is -

1. 1-Methyl-aminopropane

2. Butan-2-amine

3. 2-Methyl-2-aminopropane

4. None of the above

The correct order of increasing reactivity of C-X bond towards nucleophile in the following compound is

[2010]

1. I<II<IV<III

2. II<III<I<IV

3. IV<III<I<II

4. III<II<I<IV

Aniline is reacted with bromine water and the resulting product is treated with an aqueous solution of sodium nitrite in presence of dilute hydrochloric acid. The compound so formed is converted into a tertafluoroborate which is subsequently heated. The final product is    

1. 1,3,5-tribromobenzene

2. p-bromofluorobenzene

3. p-bromoaniline

4. 2,4,6-tribromofluorobenzene

Alkyl halide (RX) on treatment with KCN followed by reduction leads to the formation of:

1. RNH₂

2. RCH₂NH₂

3. RH + NH₃

4. RCH₃ + N₂