# NEET Physics Nuclei Questions Solved

Consider a hydrogen like atom whose energy in nth exicited state is given by  when this excited atom makes a transition from excited state to ground state, most energetic photons have energy ${\mathrm{E}}_{\mathrm{max}}$ = 52.224 eV and least energetic photons have energy ${\mathrm{E}}_{\mathrm{min}}$ = 1.224 eV. The atomic number of atom is
(a) 2                 (b) 5
(c) 4                 (d) None of these

(a) Maximum energy is liberated for transition ${\mathrm{E}}_{\mathrm{n}}\to 1$ and minimum energy for  ${\mathrm{E}}_{\mathrm{n}}\to {\mathrm{E}}_{\mathrm{n}-1}$
Hence          ……(i)
and …..(ii)
Solving equations (i) and (ii) we get
and  and n = 5
Now . Hence Z = 2

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