NEET Physics Nuclei Questions Solved

In a hypothetical Bohr hydrogen, the mass of the electron is doubled. The energy E0 and the radius r0 of the first orbit will be (a0 is the Bohr radius) 
(a) E0=-27.2 eV; r0=a0/2
(b) E0=-27.2 eV; r0=a0
(c) E0=-13.6 eV; r0=a0/2
(d) E0=-13.6 eV; r0=a0

(a) Here radius of electron orbit r ∝ 1/m and energy E ∝ m, where m is the mass of the electron.
Hence energy of hypothetical atom
E0=2×-13.6 eV=-27.2 eV and radius r0=a02

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