# NEET Physics Nuclei Questions Solved

A hydrogen atom in its ground state absorbs 10.2 eV of energy. The orbital angular momentum is increased by

(a) $1.05×{10}^{-34}$ J-sec                 (b) $3.16×{10}^{-34}$ J-sec
(c) $2.11×{10}^{-34}$ J-sec                 (d) $4.22×{10}^{-34}$J-sec
(Given Planck constant h = $6.6×{10}^{-34}$ J-sec)

(a) Electron after absorbing 10.2 eV energy goes to its first excited state (n=2) from ground state (n = 1).
$\therefore$ Increase in momentum = $\frac{\mathrm{h}}{2\mathrm{\pi }}$

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