NEET Physics Nuclei Questions Solved


An energy of 24.6 eV is required to remove one of the electrons from a neutral helium atom. The energy (in eV) required to remove both the electrons from a neutral helium atom is 
(a) 79.0              (b) 51.8
(c) 49.2              (d) 38.2

(a) After the removal of first electron remaining atom will be hydrogen like atom.
So energy required to remove second electron from the atom E=13.6×221=54.4 eV
Total energy required = 24.6 + 54.4 = 79 eV.

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