A nucleus with Z = 92 emits the following in a sequence:
α,β-,β-,α,α,α,α,α,β-,β-,α,β+,β+,α. The Z of the resulting nucleus is 
(a) 74              (b) 76
(c) 78              (d) 82

(c) ZResulting nucleus=92-8×2+4×1-2×1=78

Difficulty Level:

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