NEET Physics Nuclei Questions Solved

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A radioactive element X90238 decay into Y83222. The number of β-particles emitted are

(a) 4             (b) 6
(c) 2             (d) 1

(d) Number of α-particles emitted =238-2224=4 
This decreases atomic number to 90-4×2 = 82
Since atomic number of  Y83222 is 83, this is possible if one β-particle is emitted.

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