NEET Physics Nuclei Questions Solved

In the reaction H12+H13He24+n01. If the tending energies of H12,H13 and He24 are respectively a,b and c (in MeV), then the energy (in MeV) released in this reaction is
(a) c+a-b           (b) c-a-b
(c) a+b+c          (d) a+b-c 

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