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NEET Physics Nuclei Questions Solved

In the reaction ${}_{1}^{2}H + {}_{1}^{3}H \to {}_{2}^{4}{He} + {}_{0}^{1}n$ . If the tending energies of ${}_{1}^{2}H, {}_{1}^{3}H$ and ${}_{2}^{4}{He}$ are respectively a,b and c (in MeV), then the energy (in MeV) released in this reaction is
(a) c+a-b (b) c-a-b
(c) a+b+c (d) a+b-c

(b) During fusion binding energy of daughter nucleus is always greater than the total energy of the parent nuclei so energy released = c – (a + b) = c – a – b

Difficulty Level:

(1)
12%
(2)
59%
(3)
6%
(4)
24%