# NEET Physics Nuclei Questions Solved

In the reaction ${}_{1}{}^{2}\mathrm{H}+{}_{1}{}^{3}\mathrm{H}\to {}_{2}{}^{4}\mathrm{He}+{}_{0}{}^{1}\mathrm{n}$. If the tending energies of ${}_{1}{}^{2}\mathrm{H},{}_{1}{}^{3}\mathrm{H}$ and ${}_{2}{}^{4}\mathrm{He}$ are respectively a,b and c (in MeV), then the energy (in MeV) released in this reaction is
(a) c+a-b           (b) c-a-b
(c) a+b+c          (d) a+b-c

(b) During fusion binding energy of daughter nucleus is always greater than the total energy of the parent nuclei so energy released = c – (a + b) = c – a – b

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