If the binding energy per nucleon in and nuclei are respectively 5.60 MeV and 7.06 MeV, then energy of reaction is
(a) 19.6 MeV (b) 2.4 MeV
(c) 8.4 MeV (d) 17.3 MeV
(d) B.E. of = 39.20 MeV and =28.24 MeV
Hence binding energy of 2=56.48 MeV
Energy of reaction = 56.48-39.20 = 17.28 MeV .