The gas absorbs 100 J heat and is simultaneously compressed by a constant external pressure of 1.50 atm from 8 lit. to 2 lit. in volume. Hence E will be-

1. -812 J

2. 812 J

3. 1011 J

4. 911 J

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If G=H-TS and G=H+TdGdTP then variation of EMF of a cell E, with temperature T, is given by

1. HnF 

2. GnF

3. SnF

4. -SnF

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The standard heat of combustion of Al is -837.8 kJ mol-1 at 25C which of the following releases 250 kcal of heat ?

1. The reaction of 0.624 mol of Al

2. The formation of 0.624 mol of Al2O3

3. The reaction of 0.312 mol of Al

4. The formation of 0.150 mol of Al2O3

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CP-CV=R. This R is :

1. Change in K.E.

2. Change in rotational energy

3. work done which system can do on expanding the gas per mol per degree increase in temperature

4. All correct

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Heat of neutralisation of oxalic acid is -25.4 K cal mol-1 using strong base, NaOH. Hence enthalpy change of the process is H2C2O42H++C2H42- is-

1. 2.0 kcal

2. -11.8 kcal

3. 1.0 kcal

4. -1.0 kcal

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5 moles of nitrogen gas are enclosed in an adiabatic cylindrical vessel. The piston itself is a rigid light cylindrical container containing 3 moles of Helium gas. There is a heater which gives out a power 100 cal to the nitrogen gas. A power of 30 cal is transferred to Helium through the bottom surface of the piston.

The rate of increment of temperature of the nitrogen gas assuming that the piston moves slowly :

1. 2K/sec

2. 4K/sec

3. 6K/sec

4. 8K/sec

Concept Questions :-

CP and CV and Relation for Real Gas
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During the isothermal mixing of ideal gases at pressure, p, the entropy change per mole for the mixing process is-R xi ln xi where x1, x2,....,xi are the mole fractions of the components, 1, 2,....,i of the mixture. Assuming ideal gas behavior, calculate S for the mixing of 0.8 mole of N2 and 0.2 mole of O2.(at 25C and 0.9 atm) [1 eu = cal/deg]

1. 0.9943 eu

2. 0.7533 eu

3. 0.6798 eu

4. 0.7112 eu

Concept Questions :-

Spontaneity and Entropy
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An ideal gas can be expanded from an initial state to a certain volume through two different processes, (A) PV2=K (B) P=KV2, where K is a positive constant. Then, choose the correct option from the following.

1. Final temperature in (A) will be greater than in (B)

2. Final temperature in (B) will be greater than in (A)

3. Work done by the gas in both the processes would be equal

4. Total heat given to the gas in (A) is greater than in (B)

Concept Questions :-

Extensive and Intensive Properties
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For the reaction : X2O4l2XO2gE=2.1 kcal. S=20 cal/K at 300 K. Hence G is :

1. 2.7 kcal

2. -2.7 kcal

3. 9.3 kcal

4. -9.3 kcal

Concept Questions :-

Gibbs Energy Change
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Heat of hydrogenation of ethene is x1 and that of benzene is x2. Hence resonance energy is-

1. x1-x2

2. x1+x2

3. 3x1-x2

4. x1-3x2

Concept Questions :-

Thermochemistry
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