The correct calculate value for H for

M(s) M2+(ag)

From following arbitrary value

M(s) M(g) ;H = 1000KJ mol-1M(g) M+(g) ; H = 750KJ mol-1M+(g)M2+(g);H = 1200KJ mol-1M2+(g)+aq M2+(aq.); H = -1800KJ mol-1

(A) 1950 KJ mol-1 

(B) 1150 KJ mol-1 

(C) 2300 KJ mol-1 

(D) None of these

Concept Videos :-

#8 | Ionisation Enthalpy: Introduction
#9 | Calculation of Ionisation Enthalpy
#10 | Factors affecting Ionisation Enthalpy
#11 | Trends in Ionisation Enthalpy
#12 | Application of Ionisation Enthalpy
#13 | Solved Problems

Concept Questions :-

Ionization Energy (IE)

H =Hsub+IE1+IE2+Hhydration=1000+750+12000+(-1800)H=1150 KJ mol-1

Difficulty Level:

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