For a reaction at equilibrium-

1. G=G=0

2. G=0 but not G

3. G=0 but not G

4. G=G0

Concept Questions :-

Gibbs Energy Change
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Using only the following data:

(I) Fe2O3s+3COg2Fe(s)+3CO2(g);H=-26.8 kJ

(II) Fes+COgFeOs+COg;H=+16.5 kJ

the H value, in kilojoules, for the reaction

Fe2O3s+COg2FeOs+CO2g is calculated to be:

1. -43.3

2. -10.3

3. +6.2

4. +10.3

Concept Questions :-

Enthalpy and It's Type
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82 litres of carbon dioxide are produced at a pressure of 1 atm by the action of acid on a metal carbonate. The work done by the gas (in calories) in pushing back the atmosphere is (R = 0.082 litre-atm deg-1mol-1)

1. 1000

2. 820

3. 1640

4. 2000

Concept Questions :-

First Law of Thermodynamics
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Among the following, the reaction for which H=E is-

1. PCl5gPCl3g+Cl2g

2. H2g+Cl2g2HClg

3. C2H5OHl+3O2g2CO2g+3H2Ol

4. C2H4g+H2gC2H6g

Concept Questions :-

First Law of Thermodynamics
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For which change HE

1. H2+I22HI

2. HCl+NaOHNaCl+H2O

3. Cs+O2gCO2g

4. N2+3H22NH3

Concept Questions :-

Enthalpy and It's Type
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Enthalpy change when 1.00 g water is frozen at 0C, is :

Hfus=-1.435 kcal mol-1

1. 0.0797 kcal

2. -0.0797 kcal

3. 1.435 kcal

4. -1.435 kcal

Concept Questions :-

Enthalpy and It's Type
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One mole of hydrogen gas at 25C and 1 atm pressure is heated at constant pressure until its volume has doubled. Given that Cv for hydrogen is 3.0 cal deg-1 mol-1, the H and E for this process are-

1. H = 1490 cal and E = 894 cal

2. H E= 1490 cal

3. H = 894 cal and E= 1490 cal

4. H E= 894 cal

Concept Questions :-

CP and CV and Relation for Real Gas
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The enthalpy change of the reaction

Al2Cl6s+6Nas2Als+6NaCls is -257 kcal.

Given the heat of formation of NaCl(s) is 98.0 kcal, the heat of formation of Al2Cl6s is-

1. 158 kcal

2. -331 kcal

3. -166 kcal

4. 316 kcal

Concept Questions :-

Thermochemistry
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Some of the thermodynamic parameters are state variables while some are process variables. Some grouping of the parameters are given. Choose the correct one-

1. State variables : Temperature, No. of moles

Process variables : Internal energy, work done by the gas

2. State variables : Volume, Temperature

Process variables : Internal energy, work done by the gas

3. State variables : work done by the gas, heat rejected by the gas.

Process variables : Temperature, volume

4. State variables : Internal energy, volume

Process variables : Work done by the gas, heat absorbed by the gas

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One mole of a real gas is subjected to heating at constant volume fromP1, V1, T1 state to P2, V2, T2 state. Then it is subjected to irreversible adiabatic compression against constant external pressure of P3 atm till syatem reaches the final stateP3, V3, T3. If the constant volume molar heat capacity of real gas is CV. Find out correct expression for H from state 1 to state 3-

1. CvT3-T1+P3V1-P1V1

2. CvT2-T1+P3V2-P1V1

3. CvT2-T1+P3V1-P1V1

4. CpT2-T1+P3V1-P1V1

Concept Questions :-

CP and CV and Relation for Real Gas
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