Oxygen does not form OF6 because

1. It has a small size

2. There are no vacant d- orbitals available

3.  It has high ionization energy

4. It has a large size

Subtopic:  Group 16 - Preparation, Properties & Uses |
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The molecule having the smallest bond angle is

(1) H2O

(2) H2S

(3) H2Te

(4) H2Se

Subtopic:  Group 16 - Preparation, Properties & Uses |
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The correct statement regarding H3PO3 is:

1. Each hydrogen atom is attached to oxygen.

2. Two hydrogen atoms are attached to oxygen atoms.

3. One atom of H is attached to oxygen.

4. None of the above.

Subtopic:  Group 16 - Preparation, Properties & Uses |
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Strong oxidising agent and strong reducing agents are respectively

(1) F2, HI

(2) Cl2, HCl

(3) Br2,HBr

(4) I2, HF

Subtopic:  Group 17 - Preparation, Properties & Uses |
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Oxide of a non-metal possesses the following characterstics.

(i) It is both a proton donor and proton acceptor

(ii) It is poor conductor of electricity

(iii) It reacts readily with basic and acidic oxides

(iv) It oxidises Fe at boiling point.

The oxide is

(1) H2O

(2) CO2

(3) H2O2

(4) NO

Subtopic:  Group 16 - Preparation, Properties & Uses |
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A yellow metallic powder is burnt in a stream of fluorine to obtain a colourless gas X which is thermally stable and chemically inert. Its molecule has octahedral geometry. Another colourless gas Y with same constituent atoms as that of X is obtained when sulphur dichloride is heated with sodium fluoride. Its molecule has triangular pyramidal structure X and Y are

(1) SF4 and S2F2

(2)  SF6 and  SF4 

(3) NaF and NaCl

(4)  SF4 and SF6 

Subtopic:  Group 16 - Preparation, Properties & Uses |
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The shape and the type of hybridization (of the Cl-atom) in  the CIF3 molecule

1. 2.
3. 4.

Subtopic:  Group 17 - Preparation, Properties & Uses |
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In the nitrogen family, the H-M-H bond angle in the hybrides MH3 gradually becomes closer to 90o if we move from N to Sb. This shows that gradually  

1. The basic strength of hybrides increases.
2. Pure p-orbitals (almost) are used for M-H bonding.
3. The bond energies of the M-H bond increase.
4. The bond pairs of electrons become nearer to the central atom.

Subtopic:  Group 15 - Preparation, Properties & Uses |
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Assertion :  In trimethyalamine (N(CH3)3), the nitrogen has a pyramidal geometry, wheres in trisilylamine (N(SiH3)3), it has a planer geometry.

Reason : In trimethylamine, nitrogen shows sp3 hybridization while in trisilyamine it shows sp2 hybridization.

  1. If both the assertion and the reason are true and the reason is a correct explanation of the assertion
  2. If both the assertion and reason are true but the reason is not a correct explanation of the assertion
  3. If the assertion is true but the reason is false
  4. If both the assertion and reason are false
Subtopic:  Group 15 - Preparation, Properties & Uses |
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Assertion : Most of the known noble gas compounds are those of xenon.

Reason : The ionisation enthalpy of xenon is very close to that of oxygen.

  1. If both the assertion and the reason are true and the reason is a correct explanation of the assertion
  2. If both the assertion and reason are true but the reason is not a correct explanation of the assertion
  3. If the assertion is true but the reason is false
  4. If both the assertion and reason are false
Subtopic:  Group 18 - Preparation, Properties & Uses |
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