NEET Chemistry Surface Chemistry Questions Solved


Graph between log x m and log P is a straight line inclined at an angle θ- 45°. When pressure of 0.5 atm and log k = 0.699, the amount of solute adsorbed per g of adsorbent will be

(A) 1 g/g adsorbent                             

(B) 1.5 g/g adsorbent

(C) 2.5 g/g adsorbent                           

(D) 0.25 g/g adsorbent

C.  xm= K·P1/n since log k=0.699, hence k=5          slope=1/n=tan 45°=1          thus, xm=5×0.5=2.5 g/g adsorbent

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